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3 years ago

Seven-tenths as a decimal

Mathematics

2 answers:

asambeis [7]3 years ago

7 0

.7 is the answer or .70 :D

Setler [38]3 years ago

7 0

<span>The decimal 0.7 could be pronounced as SEVEN TENTHS or as ZERO POINT SEVEN. There are other decimals such as hundredths or thousandths.</span>

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I suck at math haha so disregard my answers they’re most likely wrong if you could just answer all the questions shown that woul

Sedbober [7]

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3 years ago

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The midpoint of PQ is M(, –1). One endpoint is Q(3, –5). Which equations can be solved to determine the coordinates of P? Check

valkas [14]

<u>Comment</u>

If I don't know what was before the comma in M(, –1) I can't solve this

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3 years ago

Make up an equation of the form y = kx +b, the graph of which passes through the following points: A (8, –1) and B (–4, 17)

igor_vitrenko [27]

Answer:

One equation would be y= -1.5x +11

Step-by-step explanation:

Here's a table to show the coordinates

x: y:

8 -1

-------------------

-4 17

the x coor. 8 goes down by 12 to get to the next x coor. -4.

8-12= -4

the y coor. -1 goes up by 18 to get to the next y coor. 17.

-1+18= 17

therefore 18/-12 is -1.5 which can be your k in y=kx+b.

Check your answer.

-1.5*8= -12 but when you add 11, you get the y coor. -1

Do the same with the other x coor.

-4*-1.5= 6 + 11 =17

11 can be your b in the slope-intercept form equation.

One equation may be y = -1.5x +11

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3 years ago

Find the 30th term of the following sequence.

Nataly_w [17]

Answer:

-105

Step-by-step explanation:

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3 years ago

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What is the sum of the infinite geometric series? Sigma-Summation Underscript n = 1 Overscript 4 EndScripts (negative 144) (one-

Irina18 [472]

The sum of the infinite geometric series is -288.

<h2>Given that</h2>

A finite geometric series with n = 4, a₁ = -144, and r = ½.

<h3>We have to determine</h3>

What is the sum of the infinite geometric series?

<h3>According to the question</h3>

The sum of the infinite is determined by the following formula;

$\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\$

A finite geometric series with n = 4, a₁ = -144, and r = ½.

Substitute all the values in the formula;

$\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\S\infty = \dfrac{-144 (1- \dfrac{1}{2}^4)}{1-\dfrac{1}{2}}\\\\S \infty = \dfrac{-144 \times \dfrac{15}{16}}{\dfrac{1}{2}}\\\\S \infty = -270$

Therefore,

The sum of the infinite geometric series is,

$\rm S = \dfrac{a_1}{1-r}\\\\S=\dfrac{-144}{1-\dfrac{1}{2}}\\\\S = \dfrac{-144}{0.5}\\\\S = -288$

Hence, the sum of the infinite geometric series is -288.

To know more about Geometric Series click the link given below.

brainly.com/question/16037289

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2 years ago