|| Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down
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Answer:
<em>The velocity of the truck is 3.33 m/s</em>
Explanation:
<u>Law Of Conservation Of Linear Momentum </u>
The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is
P=mv.
If we have a system of bodies, then the total momentum is the sum of the individual momentums:
If some collision occurs, the velocities change to v' and the final momentum is:
In a system of two masses:
There are two objects: The m1=4000 Kg car and the m2=6000 Kg truck. The car was moving initially at v1=4 m/s and the truck was at rest v2=0. After the collision, the car moves at v1'=-1 m/s. We need to find the velocity of the truck v2'. Solving for v2':
Substituting:
The velocity of the truck is 3.33 m/s
We can solve this using the Law of Conservation of Momentum. If both marbles are in our system, the initial momentum should equal the final momentum.
The initial momentum can be solved for as so:
* 
+ 
= 
(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]
So if the system has an initial momentum of 0.042, it should have the same final momentum.
(0.06)(-0.2) + (0.03)(
) = 0.042
(0.03)() = 0.54
() = 18 [m/s]
The initial momentum can be solved for as so:
(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]
So if the system has an initial momentum of 0.042, it should have the same final momentum.
(0.06)(-0.2) + (0.03)(
(0.03)(
(