Answer:
Total Cost is 41.18 AED
Explanation:
Per day number of hours light bulbs were on=3hours
5 bulbs power consumption = 150Wx5 = 750W
Electricity usage per day = 750 x 3 = 2250Wh = 2.25kWh
April has 30 days and May has 31 days. Therefore totals days = 61days
Total power consumption = 2.25x 61 = 137.25kWh
Total Cost = 137.25x 0.30 = 41.175 AED
Answer:
the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Explanation:
Given the data in the question;
first we determine the rotational latency
Rotational latency = 60/(3600×2) = 0.008333 s = 8.33 ms
To get the longest time, lets assume the sector will be found at the last track.
hence we will access all the track, meaning that 127 transitions will be done;
so the track changing time = 127 × 15 = 1905 ms
also, we will look for the sectors, for every track rotations that will be done;
128 × 8.33 = 1066.24 ms
∴The Total Time = 1066.24 ms + 1905 ms
Total Time = 2971.24 ms
Therefore, the longest time needed to read an arbitrary sector located anywhere on the disk is 2971.24 ms
Cell membranes are 50% protein, the proteins are responsible for many biological processes. If the proteins were absent the membrane could not carry out it's intended purpose.
Answer:
v = 22.54 mph.
Explanation:
Given that,
Distance moved, d = 200 m
Time, t = 19.8 s
We need to find the runner's average speed.
We know that,
1 mile = 1609.34 m
200 m = 0.124 miles
19.8 seconds = 0.0055 h
So,
Speed = distance/time
So, the runner's average speed is 22.54 mph.
Answer:
The maximum value of the driving force is 1044.01 N.
Explanation:
Given that,
Weight of the object, W = 50 N
Force constant of the spring, k = 210 N/m
The system is undamped and is subjected to a harmonic driving force of frequency 11.5 Hz.
Amplitude, A = 4 cm
We need to find the maximum value of the driving force. The force is given by the product of mass and maximum acceleration as :
.....(1)
A is amplitude
m is mass,
is angular frequency
Angular frequency is given by :
Equation (1) becomes :
So, the maximum value of the driving force is 1044.01 N.
