Answer:
1/3
Explanation:
We can solve the problem by using the lens equation:
where
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
Here we have a divering lens, so the focal length must be taken as negative (-f). Moreover, we know that the object is placed at a distance of twice the focal length, so
So we can find q from the equation:
Now we can find the magnification of the image, given by:
Answer:
<u><em>The plank moves 0.2m from it's original position</em></u>
Explanation:
we can do this question from the constraints that ,
thus ,
<em>since the wheel is pure rolling or not slipping,</em>
<em>⇒</em>
where
<em> - speed of the wheel</em>
<em> - angular speed of the wheel</em>
<em> - radius of the wheel</em>
<em>since the wheel traverses 1 m let's say in time '' ,</em>
<em></em>
∴
⇒
the speed at the topmost point of the axle is :
⇒
this is the speed of the plank too.
thus the distance covered by plank in time '' is ,
⇒