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iogann1982 [59]
3 years ago
9

Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 x 10^4 Pa. If

the pipe widens to twice its original radius, what is the pressure in the wider section?
Physics
1 answer:
frez [133]3 years ago
5 0

Answer:

p2 = 9.8×10^4 Pa

Explanation:

Total pressure is constant and PT = P = 1/2×ρ×v^2  

So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2

from continuity we have ρ×A1×v1 = ρ×A2×v2  

v2 = v1×A1/A2  

and  

r2 = 2×r1

then:

A2 = 4×A1  

so,

v2 = (v1)/4  

then:

p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2  

p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)  

     = 9.75×10^4 Pa

    = 9.8×10^4 Pa

Therefore, the pressure in the wider section is 9.8×10^4 Pa

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Lelechka [254]

Answer:

Effective Pulling Force = 29.2(cos 62.7°) = 13.393 N

Resistance to Pulling Force = 11.7 N

Net Force acting on suitcase = 13.393 - 11.7 = 1.693 N

Distance moved = 8.44 m

Net Work = 1.693(8.44) = 14.289 ≈ 14.3 J  ANS

Explanation:

hope that makes sense homie

6 0
2 years ago
The relative density of oak wood is 0.64 .find the density in the cgs system
Zepler [3.9K]
Relative density is defined as:
 dr = ds / dw
 where:
 dr: relative density
 ds: density of the substance.
 dw: density of water.
 In this case we have the relative density of oak wood:
 dr = 0.64.
 We want to find the density of the substance: ds
 Therefore we need to know the density of water in the cgs unit system:
 dw = 1g / c ^ 3
 Finally:
 ds = dr * dw
 ds = 0.64 * 1 g / cm ^ 3
 ds = 0.64 g / c ^ 3
 The density of the oak wood in cgs is 0.64 g / cm ^ 3
6 0
3 years ago
Identify which objects will accelerate to the left, which will accelerate to the right,and those that will not accelerate. Optio
Licemer1 [7]

Answer:

The situation given in option A and B are examples for moving an object toward left side while the option C and option D are examples for moving an object toward right side. Option B will also be an example for not moving the object.

Explanation:

As per the option A statement, the force acting towards left is greater than the force acting toward right side. So the net force will be towards the direction having maximum magnitude. Thus, the box will move toward left side in option A. The same situation arises for the object in option B. But here the difference in the forces is only 1 N, so the change in the position of the object will be very less. Thus it may look like there is no acceleration in the box of option B.

Similarly, the force acting on the objects given in option C and D have magnitude greater towards the right side than towards the left side.  So these two will be accelerated toward the right side.

3 0
3 years ago
2. A ball is dropped from rest. The acceleration due to gravity is 10m/s? and the time it
d1i1m1o1n [39]

Answer:

STEP BY STEP

V = S/T

V= 10/5

V = 2 m/s

3 0
3 years ago
How are the electric field lines around a positive charge affected when a second positive charge is near it?
Lesechka [4]

Answer: The field lines bend away from the second positive charge

Explanation: opposite attracts, same repulse

4 0
3 years ago
Read 2 more answers
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