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3 years ago

8. What will be the extension of a spring of K = 10 N/m, if the load is 75g?

Physics

1 answer:

ira [324]3 years ago

4 0

Answer:

<em>The extension of the spring is 7.35 cm</em>

Explanation:

<u>Spring Force </u>

When a spring is compressed or extended by a distance x, it exerts a force given by the Hooke's Law:

F=k.x

Where k is the constant of the spring.

A mass of m=75 gr is hung to the spring of constant k=10 N/m. The force applied to the spring is the weight of the mass:

W = mg

The mass must be converted to kg:

m = 75/1000 = 0.075 kg

W=0.075*9.8

W = 0.735 N

The extension of the spring can be computed by solving for x:

$\displaystyle x=\frac{0.735}{10}$

x=0.0735 m

x = 7.35 cm

The extension of the spring is 7.35 cm

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2 years ago

8. What will be the extension of a spring of K = 10 N/m, if the load is 75g?​

8. What will be the extension of a spring of K = 10 N/m, if the load is 75g?