To find the common difference, we use the formula
where
<em>a2</em> represents the second term and <em>a1</em> represents the first term.
So plugging the second term and first term into
the formula, we have (17) - (12) which is 5.
So the common difference of
this arithmetic sequence is 5.
a. 6, 8, 10, 12, 14
Work:
a_1 = 2(1) + 4
a_1 = 6
a_2 = 2(2) + 4
a_2 = 8
a_3 = 2(3) + 4
a_3 = 10
a_4 = 2(4) + 4
a_4 = 12
a_5 = 2(5) + 4
a_5 = 14
b. 500
Work:
Since the common difference is 2, we can add 2 to each number until we reach the 20th term.
6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22 + 24 + 26 + 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 = 500
Answer:
43.99
Step-by-step explanation:
because I said it was
Answer:
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Answer:
answer choice a is correct, and no
Step-by-step explanation: