25 is the answer
hope it helps
Answer:
See Below.
Step-by-step explanation:
We want to show that the function:
Increases for all values of <em>x</em>.
A function is increasing whenever its derivative is positive.
So, find the derivative of our function:
![\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5Be%5Ex%20-%20e%5E%7B-x%7D%5Cright%5D)
Differentiate:
Simplify:
Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>
<h3>
Answer: 270.58 dollars</h3>
======================================================
Work Shown:
- A = account value after t years
- P = principal or amount deposited = 800
- r = interest rate in decimal form = 0.06
- n = number of times we compound per year = 1
- t = number of years = 5
So,
A = P*(1+r/n)^(n*t)
A = 800*(1+0.06/1)^(1*5)
A = 1070.58046208
A = 1070.58
After five years, the account will have $1,070.58 in it.
The amount of interest earned is A-P = 1070.58 - 800 = 270.58 dollars.
Answer:
yuh
Step-by-step explanation:
M = -1/2
B = 1
Equation shown is y = mx + b
