Answer:-
0.229 L
Explanation:-
Molar mass of AgBr = 107.87 x 1 + 79.9 x 1
=187.77 grams mol-1
Mass of AgBr = 150 grams
Number of moles of AgBr = 150 grams / 187.77 gram mol-1
= 0.8 mol
The balanced chemical equation is
NaBr (aq) + AgNO3 (aq)--> AgBr(s) + NaNO3(aq)
From the equation we can see that
1 mol of AgBr is produced from 1 mol of AgNO3.
∴ 0.8 mol of AgBr is produced from 1 x 0.8 / 1 = 0.8 mol of AgNO3.
Strength of AgNO3 = 3.5 M
Volume of AgNO3 required = Number of moles / strength
= 0.8 moles / 3.5
=0.229 L
Answer:10,000 kg
Explanation:I went on my calculator and did 1,000 × 250 ÷ 25 or -25 to get 10,000 or -10,000 ;)
<h3><u>Answer;</u></h3>
Reduces the amount of work needed to move an object.
<h3><u>Explanation;</u></h3>
- <u>A simple machine is any device that reduces human effort to do work. They include, levers, inclined plane, pulleys, etc</u>.
- Simple machines make work easier by multiplying, reducing, or changing the direction of a force and also by changing the distance the force acts through.
- Simple machines cannot change the amount of work done, however, they can reduce the effort force that is required to do the work. This is to mean, machines can neither increase or reduce the energy involved in doing work.
The reactants are not good a good substitute for sodium azide in airbags because sodium bicarbonate and acetic acid produces far less volume of gas than sodium azide.
<h3>Which of the reactants produces greater volume of gas? </h3>
The chemical equation of the reactions is given below:
- Sodium azide reaction: 2 NaN₃ → 2 Na + 3 N₂
- Sodium bicarbonate and acetic acid reaction: Na₂CO₃ + CH₃COOH → CH₃COONa + H₂O + CO₂
The molar volume of all gases is 22.4 L
Based on the mole ratio, sodium bicarbonate and acetic acid produces far less volume of gas than sodium azide. Thus, the reactants are not good a good substitute for sodium azide.
In conclusion, the molar volume of gases is constant.
Learn more about gas volume at: brainly.com/question/10929120
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Reacting mass=11.0
molar mass =53.45
moles=reacting Mass /molar mass
11.0/53.45=0.21moles