All categories

2 years ago

PLS HELP: CHEMISTRY

Chemistry

1 answer:

user100 [1]2 years ago

7 0

Answer:

3.59x10^21 molecules

Explanation:

1mole of a substance contains 6.02x10^23 molecules.

Therefore, 1mole of C8H18 will also contain 6.02x10^23 molecules

1mole of C8H18 = (12x8) +(18x1) = 96 + 18 = 114g.

1mole (i.e 114g) oh C8H18 contains 6.02x10^23 molecules.

Therefore, 0.68g of C8H18 will contain = (0.68 x 6.02x10^23)/114 = 3.59x10^21 molecules

You might be interested in

THE GEOCENTRIC MODEL

Mars2501 [29]

Answer:

Explanation:

6 0

2 years ago

What does the process of natural selection involve

Lorico [155]

Answer:

Only the organisms best adapted to their environment tend to survive and transmit their genetic characters in increasing numbers to succeeding generations while those less adapted tend to be eliminated.

Explanation:

According to Darwin's Theory of Evolution.

Hope this helped.

5 0

3 years ago

Which term is used to describe all the habitats around the world?

OlgaM077 [116]

Answer:

ecosystem diversity

Explanation:

hope this helped

5 0

1 year ago

at a given tempature gas with a pressure of 150 kpa has volume of 0.8 l if the pressure decreases to 75kpa and the temperature r

vova2212 [387]

<span>P*V/T=constant
so P*V= constant*T
if T doesn't change then
P*V= constant
so 150kPa*0.8L=75kPa*xL
xL=150kPa*0.8L/75kPa=1.6L
hope it help</span>

8 0

3 years ago

SOLVE The density of a gas is 0.68 g/mL. What amount of space would 23.8 g of this gas occupy?

Contact [7]

Answer:

<h2>The answer is 35 mL</h2>

Explanation:

Density of a substance can be found by using the formula

$Density(\rho) = \frac{mass}{volume}$

From the question we are finding the amount of space the gas will occupy that's the volume of the gas

Making volume the subject we have

$volume = \frac{mass}{Density}$

From the question

mass = 23.8 g/mL

Density = 0.68 g/mL

Substitute the values into the above formula and solve

That's

$volume = \frac{23.8}{0.68}$

We have the final answer as

Hope this helps you

6 0

3 years ago