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4vir4ik [10]
2 years ago
12

PLS HELP: CHEMISTRY

Chemistry
1 answer:
user100 [1]2 years ago
7 0

Answer:

3.59x10^21 molecules

Explanation:

1mole of a substance contains 6.02x10^23 molecules.

Therefore, 1mole of C8H18 will also contain 6.02x10^23 molecules

1mole of C8H18 = (12x8) +(18x1) = 96 + 18 = 114g.

1mole (i.e 114g) oh C8H18 contains 6.02x10^23 molecules.

Therefore, 0.68g of C8H18 will contain = (0.68 x 6.02x10^23)/114 = 3.59x10^21 molecules

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If 11.9 kJ are used to heat a sample of water the temperature increases from 20.0°C to
Kipish [7]

Answer:

m=4.51g

Explanation:

Hello!

In this case, since the energy involved during a heating process is shown below:

Q=mCp\Delta T

Whereas the specific heat of water is 4.184 J/(g°C), we can compute the heated mass of water by the addition of 11.9 kJ (11900 J) of heat as shown below:

m=\frac{Q}{Cp\Delta T}

Thus, by plugging in, we obtain:

m=\frac{11900J}{4.184\frac{J}{g\°C}(650\°C-20.0\°C)}\\\\m=4.51g

Best regards!

7 0
2 years ago
What does Avogadro's law state and what is the formula​
sertanlavr [38]

The law is approximately valid for real gases at sufficiently low pressures and high temperatures. The specific number of molecules in one gram-mole of a substance, defined as the molecular weight in grams, is 6.02214076 × 1023, a quantity called Avogadro's number, or the Avogadro constant.

5 0
2 years ago
Read 2 more answers
Lisa is using a spring scale to measure the weight of a wooden block. She weighs the wooden block a total of five times with the
Alchen [17]

Answer:

A)The spring scale has a high level of precision and a low level of accuracy.

Explanation:

Hope it works for u guys

3 0
3 years ago
Explain whether areas B and D show the same season.
torisob [31]
They do not show the same season. one is faced a different part of the sun
4 0
2 years ago
An inflatable toy starts with 1.05 moles of air and a volume of 5.17 liters. When fully inflated, the volume is 8.00 liters. If
padilas [110]

Answer:-  1.62 moles

Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.

\frac{V_1}{V_2}=\frac{n_1}{n_2}

from given data, V_1 = 5.17 L, n_1 = 1.05 moles

V_2 = 8.00 L, n_2 = ?

Let's plug in the values in the formula:

\frac{5.17L}{8.00L}=\frac{1.05moles}{n_2}

On cross multiply:

n_2=\frac{8.00L(1.05moles)}{5.17L}

n_2 = 1.62 moles

So, now the toy contains 1.62 moles of the air.


5 0
3 years ago
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