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kramer
3 years ago
13

Summarize: How are matter and substances related?

Chemistry
1 answer:
bearhunter [10]3 years ago
8 0

All substances are matter but all matters are not substance. Matter is generally a loose term used in respect to a substance. Matter and substance are sometimes used for the same context, this is certainly not correct. Various examples have already proved that a matter will not always be a substance depending on its physical nature, but a substance is always a matter.

(cc/ to Taskmasters , I just switched it up a little bit.)

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IgorC [24]

Answer:

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Explanation:

3 0
2 years ago
What does surface tension mean?
Volgvan

Surface tension, property of a liquid surface displayed by its acting as if it were a stretched elastic membrane. This phenomenon can be observed in the nearly spherical shape of small drops of liquids and of soap bubbles. Because of this property, certain insects can stand on the surface of water.

7 0
2 years ago
Read 2 more answers
State the difference between sugar in water and pebbles in water
Usimov [2.4K]
Sugar is made of molecules that are bonded together based on the positively and negatively charged areas.  They will slowly dissolve in water.  Pebbles are solids.  They will sit in water for a long time.  Though shale pebbles will break apart or fall apart.
6 0
2 years ago
if five gases contained in a cylinder each exert a pressure of 1.0 atm what is the total pressure exerted by the gases
UNO [17]

Answer:5.0 atm

Explanation:

See attached photo

6 0
2 years ago
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When adjusted for any changes in ΔHΔH and ΔSΔS with temperature, the standard free energy change ΔG∘TΔGT∘Delta G_{T}^{\circ} at
STALIN [3.7K]

The equilibrium constant is 0.0022.

Explanation:

The values given in the problem is

ΔG° = 1.22 ×10⁵ J/mol

T = 2400 K.

R = 8.314 J mol⁻¹ K⁻¹

The Gibbs free energy should be minimum for a spontaneous reaction and equilibrium state of any reaction is spontaneous reaction. So on simplification, the thermodynamic properties of the equilibrium constant can be obtained as related to Gibbs free energy change at constant temperature.

The relation between Gibbs free energy change with equilibrium constant is ΔG° = -RT ln K

So, here K is the equilibrium constant. Now, substitute all the given values in the corresponding parameters of the above equation.

We get,

1.22 * 10^{5} = - 8.314* 2400 * ln K

\\ 1.22 * 10^{5} = -19953.6 * ln K

ln K = \frac{-1.22*10^{5} }{19953.6} =-6.114\\\\k =e^{-6.114}=0.0022

So, the equilibrium constant is 0.0022.

4 0
3 years ago
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