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Aliun [14]
3 years ago
15

WILL GIVE BRAINLIEST!!! Given tan(theta) = 4/3 and pi < theta < (3pi)/2, find cos(2theta).

Mathematics
2 answers:
Korvikt [17]3 years ago
4 0

Answer:

answer d on edge

Step-by-step explanation:

the guy above got me

babymother [125]3 years ago
3 0

Answer:  \cos 2 \theta = \dfrac{-7}{25}

Step-by-step explanation:

Given: \tan \theta = \dfrac{4}{3}  and  \pi < \theta< \dfrac{3\pi }{2}

To find: \cos 2 \theta

Now as we know

\cos 2x = \dfrac{1- \tan ^2 x}{1+ \tan ^2 x}

So we have

\cos 2 \theta = \dfrac{1-(\dfrac{4}{3} )^2}{1+(\dfrac{4}{3} )^2} \\\\\Rightarrow \cos 2 \theta = \dfrac{1- \dfrac{16}{9} }{1+ \dfrac{16}{9} } = \dfrac{\dfrac{9-16}{9} }{\dfrac{9+16}{9}} = \dfrac{-7}{25}

Therefore d. is the correct option

Hence , \cos 2 \theta = \dfrac{-7}{25}

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We can set up the following equation to solve for the value of x:

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Subtract 2x from both sides:

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Add 21 to both sides to isolate and solve for the value of x:

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We must verify if we have the correct value for x by plugging in 8 into the equality statement:

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