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Nady [450]
3 years ago
11

Maya is taking her friends to a concert. Each ticket costs $25, and souvenir T-shirts are $12 each. There is a $4 service fee fo

r the entire purchase. She has $130. If she buys 3 tickets, how many T-shirts can she buy? If x = number of tickets and y = number of T-shirts, which of the following inequalities could you use to answer the problem?
a. 25x+12y 130
b. 25x+12y+4 130
c. 25x+12y+4 130
d. x+y < 130
Mathematics
1 answer:
evablogger [386]3 years ago
8 0

Answer:

25x+12y+4 \leq 130

Step-by-step explanation:

Here, x represents the number of tickets and y represents the number of T-shirts.

As per the statement:

Each ticket costs $25,  and souvenir T-shirts are $12 each

⇒Total cost of ticket = 25x and Total cost for T-shirt = 12y

It is also given that there is a $4 service fee for the entire purchase.

25x+12y+4

Since, she has $130

⇒25x+12y+4 \leq 130

Therefore, an inequality could you use to answer the problem is, 25x+12y+4 \leq 130

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You jog 2 kilometers in 12 minutes. Your friend jogs 3 kilometers in 16.5 minutes. Who jogs faster? You jog faster. Your friend
Darya [45]

Answer:

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Step-by-step explanation:

Speed = Distance(km)/Time(hours)

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend's will finish a 5km race at a speed of 18.18 km/hr

Your speed is :

You jog 2 kilometers in 12 minutes.

Convert 12 minutes to hours

60 minutes = 1 hour

12 minutes = x

x = 12/60

x = 1/5 hour

Your speed is calculated as:

2km/1/5hour

= 2 km ÷ 1/5 hour

= 2 × 5

= 10 km/hr

Your friend's speed is calculated as:

Your friend jogs 3 kilometers in 16.5 minutes.

Convert 16.5 minutes to hours

60 minutes = 1 hour

16.5 minutes = x

x = 16.5/60

x = 0.275 hour

Your speed is calculated as:

3km/0.275 hour

= 10.909090909 km/hr

Approximately = 10.91km/hr

a) Who jogs faster?

Your friend jogs faster because he jogs with a speed of 10.91 km/hr

Question 2 How much sooner will the faster jogger finish a five-kilometer race?

Your friend jogs faster, hence:

3 km = 10.91 km/hr

5km = x

x = 5 × 10.91/3

x = 18.183333333 km/hr

Your friend's will finish a 5km race at a speed of 18.18 km/hr

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A sound wave travels through iron at a rate of 5120\,\dfrac{\text{m}}{\text{s}}5120
Jet001 [13]

The rate at which the sound travels in km/hr is 0.142km/hr

<h3>Conversion of m/s to km/hr</h3>

If a sound wave travels with a speed of 5120m/s, in order to convert to km/he, we will use the conversion factor below;

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Using the conversion factor in our dimensional analysis

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6 0
2 years ago
Help with these precalculus problems, please.
likoan [24]
Yay, easy peasy, nice refresher


53. evaluate for x=infinity
we get 100/(infiniy^2-5) which is basically 100/infinity which is a very small number so about 0



54.
vertical assemtotes, neato
that is where the denomenator equals 0
but wait, simplify first
ok, fraction is simplified (anything factored out would be a hole)
so set the denom to 0 and solve
x^2-5=0
(x-√5)(x+√5)=0
x=-√5 and √5
vertical assemtotes at x=-√5 and x=√5




55. horizontal assemtotes
for the function p(x)/f(x)

if p(x) has lower degree than f(x) then y=0 is the horizontal assemtote

if p(x) has equal degree to f(x) then divide the leading coefients of p(x) and f(x)

if p(x) has greater degree than f(x) then we got slant assemtotes

100/(x^2-5)
100 has lower degree than x^2
y=0 is the horizontal assemtote



56. evalate for x=-5
we get -150/-10=150/10=15
the limit is 15



57. that negative on the right side means that we must approach it from the left
let's see if we can factor out the denomenator
nope
so go and evaluate values like 4, 4.5, 4.9, etc, approaching x=5 from the left
we keep getting smaller and smaller valuse
this make sense because as x approaches 5, we get 30(c)/(c-5) where c is close to 5, and as c appraoches 5 very close, the top part is appraoching 150 but the bottom approaches a very small negative number, and if we do something like 150/-0.00000000001, we get a very negative number
the limit is negative infinity

alternately, you could figure that there is a vertical assemtote at x=5 so we can see that if we aproximaate closer and closer values, we get smaller values. so from what we know about assemtotes, expecially vertical ones, we say that it approaches negative infinity




58.
evalauating we get infintity/inifinty, not helpful
hmmm, is there a horizontal assemtote to help us?
the degree of top is higher so we got a slant assemtote
the only way is to use long division to divide the top by the bottom (see attachment)
we get
\frac{1}{2}x-\frac{1}{4}+\frac{\frac{1}{4}}{2x+1}
the slant assemtote is y=\frac{1}{2}x-\frac{1}{4}
as you can see, as x approaches infinity, y also will approach infinity











ANSWERS:
53. 0
54. VA is x=-√5 and x=√5
55. HA is y=0
56. the limit is 15
57. the limit is -∞
58. the limit is ∞

6 0
3 years ago
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