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Anastasy [175]
2 years ago
12

Given the recursive formula below, what are the first four terms of the sequence

Mathematics
1 answer:
Ivan2 years ago
8 0

Answer:

c

Step-by-step explanation:

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I’m confused on this type of math
slega [8]

Answer:

all you do is add

Step-by-step explanation:

8 0
3 years ago
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PLEASE HURRY 50 POINTS AND I WILL VOTE U BRAINLY
dsp73

Answer:

In the exponential regression model, a represents the initial value and b represents the growth factor.

Step-by-step explanation:

a+bx= y

b would represent your slope and a would be your y intercept.

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2 years ago
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On the graph of the equation X-4Y= -16 what is the value of the Y-intercept?
Nonamiya [84]

we can always find the x-intercept by simply settting y = 0, and solving for "x".

and we can always find the y-intercept by simply setting x = 0 and solving for "y".


\bf x-4y=-16\implies \stackrel{x=0}{0-4y=-16}\implies y=\cfrac{-16}{-4}\implies y=4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill (0,4)~\hfill

8 0
2 years ago
A woman takes 121212 equal-sized steps. She walks a total of 10 \text { yards}10 yards10, start text, space, y, a, r, d, s, end
kramer

Answer:

30 inches

Step-by-step explanation:

She takes 12 equal sized steps and they all add up to 10 yards.

The length of each step (in yards) is:

10 / 12 = 5/6 yards

The question requires the answer in inches, therefore, we must convert this to inches:

1 yard = 36 inches

5/6 yards = 5/6 * 36 = 30 inches

Each step is 30 inches long.

5 0
3 years ago
One of the earliest applications of the Poisson distribution was in analyzing incoming calls to a telephone switchboard. Analyst
grandymaker [24]

Answer:

(a) P (X = 0) = 0.0498.

(b) P (X > 5) = 0.084.

(c) P (X = 3) = 0.09.

(d) P (X ≤ 1) = 0.5578

Step-by-step explanation:

Let <em>X</em> = number of telephone calls.

The average number of calls per minute is, <em>λ</em> = 3.0.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.0.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...

(a)

Compute the probability of <em>X</em> = 0 as follows:

P(X=0)=\frac{e^{-3}3^{0}}{0!}=\frac{0.0498\times1}{1}=0.0498

Thus, the  probability that there will be no calls during a one-minute interval is 0.0498.

(b)

If the operator is unable to handle the calls in any given minute, then this implies that the operator receives more than 5 calls in a minute.

Compute the probability of <em>X</em> > 5  as follows:

P (X > 5) = 1 - P (X ≤ 5)

              =1-\sum\limits^{5}_{x=0} { \frac{e^{-3}3^{x}}{x!}} \,\\=1-(0.0498+0.1494+0.2240+0.2240+0.1680+0.1008)\\=1-0.9160\\=0.084

Thus, the probability that the operator will be unable to handle the calls in any one-minute period is 0.084.

(c)

The average number of calls in two minutes is, 2 × 3 = 6.

Compute the value of <em>X</em> = 3 as follows:

<em> </em>P(X=3)=\frac{e^{-6}6^{3}}{3!}=\frac{0.0025\times216}{6}=0.09<em />

Thus, the probability that exactly three calls will arrive in a two-minute interval is 0.09.

(d)

The average number of calls in 30 seconds is, 3 ÷ 2 = 1.5.

Compute the probability of <em>X</em> ≤ 1 as follows:

P (X ≤ 1 ) = P (X = 0) + P (X = 1)

             =\frac{e^{-1.5}1.5^{0}}{0!}+\frac{e^{-1.5}1.5^{1}}{1!}\\=0.2231+0.3347\\=0.5578

Thus, the probability that one or fewer calls will arrive in a 30-second interval is 0.5578.

5 0
3 years ago
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