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3 years ago

Let g(x)=x^2+bx+11. The point (-1,8) lies on graph of g. Find value of b.

Mathematics

1 answer:

ikadub [295]3 years ago

6 0

Answer:

b=4

Step-by-step explanation:

g(x)=x^2+bx+11

When x = -1 g(x) = 8

8 = (-1)^2 +b(-1) +11

8 = 1 -b+11

Combine terms

8 = 12-b

Subtract 12 from each side

8-12 = 12-b-12

-4 = -b

Multiply by -1

4 = b

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interchAnge

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2 years ago

Let g(x)=x^2+bx+11. The point (-1,8) lies on graph of g. Find value of b.​

Let g(x)=x^2+bx+11. The point (-1,8) lies on graph of g. Find value of b.