Answer: Look at it this way, you are adding 4.2, .5 times. So if you find what 1.5 is of 4.2 you then add that to 4.2. The 1 stands for how many times the number is being multiplied by. So in this case the number is only being multiplied once. Then we move onto the decimal point which says that the number is being multiplied by .5 times. This means that 2.1 (which is half of 4.2) is being added onto 4.2. Hope this makes sense. I always use a calculator for multiplying so its hard to put the process into words haha.
Step-by-step explanation:
Answer: quarts
Step-by-step explanation: 4 cups = 1 quart
Answer:

Step-by-step explanation:
I hope I did this right:
So first thing to do is set up the equation.

Next thing to to is subtract 1/3 from both sides to get:

Next up, you will multiply each of the fractions by the opposing value
(multiply 1/8 by 3 and 1/3 by 8)


Alright almost done, by multiplying 24 by 5 you get 120, that will go in the numerator to make the math a lot easier.
K = 

Finally, you subtract 123 over 24 by 8 over 24.
K = 
Then just simplfy the 115/24 to get

Answer:
87.92
Step-by-step explanation:
you have to multiply 3.14 by 2 which will give you 6.28, then you multiply 6.28 by 14 which gives you 87.92. hope this helps
Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P(
>
) = 0.05
P(Z >
) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;



x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.