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vovikov84 [41]
3 years ago
8

Make a conjecture: How many solutions does a quartic equation x4 + ax3 + bx2 + cx + d = 0 have? Explain.

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
5 0

Answer:

It has 4 solutions

Step-by-step explanation:

Quartic equations are simply defined as polynomials that have a degree of four.

Therefore, it will have four roots. These 4 roots are complex roots because they may have real and imaginary solutions. I said it may have real and imaginary roots because it's not every quartic equation that will have four real roots because for example, it could have real roots of maybe 0, 1, 2, 3, 4 and also imaginary roots to make it four roots in total.

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Answer:

3. y = -3x + 2

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Step-by-step explanation:

Slope-intercept form equation is given as y = mx + b.

3. First, using two points on the line, (0, 2) and (1, -1), find the slope (m).

Slope (m) = change in y / change in x = (-1 - 2)/(1 - 0) = -3/1

m = -3

Find the y-intercept (b):

The y-intercept (b) = 2 (this is where the line intercepts the y-axis)

b = 2

✅To write the equation, substitute m = -3 and b = 2 into y = mx + b

Thus:

y = -3x + 2

4. Using two points on the line, (2, 1) and (0, -5), find the slope (m).

Slope (m) = change in y / change in x = (-5 - 1)/(0 - 2) = -6/-2 = 3

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b = -5

✅To write the equation, substitute m = 3 and b = -5 into y = mx + b

Thus:

y = 3x + (-5)

y = 3x - 5

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Frank and Linda just finished a meal and received their bill for $47.60. They would like to leave their server a 20 percent tip.
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OR

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