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Yakvenalex [24]
2 years ago
6

Solve 2x + 4 ( 2x + 7 ) + 3 (2x + 4)

Mathematics
2 answers:
Bond [772]2 years ago
7 0

Answer:

merhabalar !

HAVE A NİCE DAY

horsena [70]2 years ago
4 0
2x+4(2x+7)+3(2x+4)
2x+8x+28+6x+12
16x+40

16x+40 would be the answer you can’t solve it any further
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What are the first 4 terms in the sequence represented by the expression 2n+3?
alekssr [168]

Answer:

cccccc

Step-by-step explanation:

hope this helps.

4 0
2 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
What is eqivelent to 6x=42
V125BC [204]
X equal 7 so 49=x7 that is what I would do at least
3 0
2 years ago
Rite an algebraic expression to represent "five plus the quotient of r and 14."
hichkok12 [17]
The answer is 3) 5+r/14

Let's go segment by segment:
<span>"five plus" means addition, so we have 5 +

</span><span>"the quotient of r and 14" is the division result, so sign / must be present: 14/r
</span>
Therefore "five plus the quotient of r and 14" is 5 + 14/r
4 0
3 years ago
Do u agree or disagree and why?
pshichka [43]

Answer:

Erm. i would disagree

Step-by-step explanation:

Because they don't look the same or anything like that.

4 0
3 years ago
Read 2 more answers
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