Answer:
6a + 15
Step-by-step explanation:
Answer:
Step-by-step explanation:
(4,6) and (20,14) are points on the line.
slope of line = (14-6)/(20-4) = 8/16= 1/2
point-slope equation for line of slope 1/2 that passes through (6,4):
y-4 = (½)(x-6)
in slope-intercept form:
y = ½x + 1
y-intercept = 1
Answer:
your answer would be D. x = 2.5 + y
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be: