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Yakvenalex [24]

2 years ago

6

Solve 2x + 4 ( 2x + 7 ) + 3 (2x + 4)

2 answers:

Bond [772]2 years ago

7 0

Answer:

merhabalar !

HAVE A NİCE DAY

horsena [70]2 years ago

4 0

2x+4(2x+7)+3(2x+4)
2x+8x+28+6x+12
16x+40

16x+40 would be the answer you can’t solve it any further

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The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

a

$y(t) = y_o e^{\beta t}$

b

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

c

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

So

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

So

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

So

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

So

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

so

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

What is the absolute value of -5+9

sleet_krkn [62]

The answer is 4
This is because |-5+9|=|-4| which equals 4

5 0

3 years ago

Adele ate lunch at a restaurant. The bill came to $90. If she left a 15% tip, how much was the

o-na [289]

Answer:

$13.50

Step-by-step explanation:

The total is $103.50.

4 0

2 years ago

Read 2 more answers

Which of these lines has the slope of -1/3

dalvyx [7]

The answer is c.

When ever it’s a negative slope it’s always a downward line.
And then just see which one makes sense

Could you please mark branliest

8 0

3 years ago

Which of the following is the graph of f(x) = -0.5|x+3| -2?

Tcecarenko [31]

Answer:

The last graph

Step-by-step explanation:

We transform functions in the following ways:

multiplying the function by a number to stretch or shrink it
multiplying by a negative to flip the orientation of the function
adding/subtracting a value to the input x to shift it horizontally
adding/subtracting a value to the output (or outside the function operation) to shift it vertically or horizontally.

Looking at the equation we can see $f(x)=-0.5\left|x+3\right|-2$

Vertically shrunk by 0.5
Negative leading coefficient to flip the graph's orientation
Horizontal shift of the vertex of 3 units to the left from (0,-2) to (-3,-2)
Vertical shift of the vertex of 2 units downward (-3,0) to (-3,-2)

The last graph has vertex (-3,-2) and satisfies the the equation.

7 0

2 years ago

Read 2 more answers