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sesenic [268]
2 years ago
15

The number of people using an older version of a spreadsheet program decreases at a rate that is proportional at any time to the

number of people still using the version at that time.
There were 10,000 people using the older version of the spreadsheet program when the new version first came out. The number of people still using the older version decreases by 20%, percent every 6 months.
Mathematics
1 answer:
Paraphin [41]2 years ago
8 0

Answer:

5842 people after 2 months

Step-by-step explanation:

Given

Initial Value: a =10000

Rate: r = 20\% every 6 months

Required

Number of people using it after 2 months

The function follows an exponential model.

So, we need to first write out the function.

If Rate: r = 20\% every 6 months

Then

Rate: r = 40\% after 1 year

r = 0.04

The function is represented as:

y = ar^x

So:

y = 10000 * 0.04^t

For 2 months, we have:

t = 2\ months

Convert to years

t = \frac{2}{12}

t = 0.167

y = 10000 * 0.04^t

y = 10000 * 0.04^{0.167}

y = 5842

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-14.4 - 8.1 = - 22.5

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2 years ago
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The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
What is the solution(s) to the equation 5a^2 - 44 = 81
Alborosie

Answer:

a=5,a=-5

Step-by-step explanation:

8 0
2 years ago
Humood's house is (-5,7)
grin007 [14]

The distance from Humood's house to the school is 500m

<h3>How to determine the distance from Humood's house to the school?</h3>

The given parameters are:

Humood's house is (-5,7)

The school is (3,1)

The distance between both points is calculated using

d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2

Substitute the known values in the above equation

d = \sqrt{(-5 - 3)^2 + (7 - 1)^2

Evaluate

d = 10

Each unit in the graph is 50m.

So, we have

Distance =10 * 50m

Evaluate the product

Distance = 500m

Hence, the distance from Humood's house to the school is 500m

Read more about distance at

brainly.com/question/1872885

#SPJ1

8 0
1 year ago
Tell you what (since some of y’all wanna lurk), imma start speaking your language. I’ll give 61 points to whomever can help me o
Alla [95]

the first answer is 14

the second answer is 0.2

6 0
3 years ago
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