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o-na [289]
3 years ago
14

Alexander makes a model of the Great Pyramid of Giza with the dimensions shown.

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

Answer:

The area of the square base is 100 in.2.

The area of each triangular face is 40 in.2.

Alexander will need 260 in.2 of paint.

Step-by-step explanation:

I dan't have an explanation I just guessed.

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Find f(x) if it is known that f(x−6)=12x−72.
zheka24 [161]

Answer:

f(x)=12x

Step-by-step explanation

We know that f(x) is our y-coordinate and x is the x-coordinate

Next we should insert x-6 as x in the equation

This is f(x)=12(x-6)-72

But if you look at this that leads to 12x-72 (ignore y-intercept)

That is our first equation  

This means that if you take out -6 from the x

You will get f(x)=12x

(Also do you go to RSM?)

5 0
3 years ago
Give brainly plsssss help meeee
irina1246 [14]

Answer:

the answer is 48, or the second choice B

Step-by-step explanation:


5 0
3 years ago
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A used-car costs $5,000. You figure you can get 4 years out of it. You drive 10,000 miles per year. Your car insurance costs $1,
JulsSmile [24]

Answer:

26,800

Step-by-step explanation:

Im not sure but thats what I got

3 0
2 years ago
Read 2 more answers
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
A function g is described below:
mamaluj [8]

Answer:

A≈1075.21

d Diameter

37

d

r

r

r

d

d

C

A

Using the formulas

A=

π

r

2

d=

2

r

Solving forA

A=

1

4

π

d

2

=

1

4

π

37

2

≈

1075.21009

Step-by-step explanation:

5 0
2 years ago
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