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shusha [124]
3 years ago
13

PLEASE HELP WILL MARK BRAINLIESTT

Mathematics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

Where the question?

Step-by-step explanation:

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Help please! <br>using quadratic formula <br>round ti nearest hundred ​
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Answer:

x = 0.19 or x = -0.76

Step-by-step explanation:

Equation: 7²-4x = 2

reordering the equation,

7x²-4x-2 = 0

Applying,

x = [-b±√(b²-4ac)]/2a..................... Equation 1

From the question,

Given: a = 7, b = -4, c = -2

Substitute these values into equation 1

x = [-4±√(-4²-(2×7×-2)]/(2×7)

x = [-4±√(16+28)]/14

x = (-4±√44)/14

Either

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x = (-4+6.63)/14

x = 2.63/14

x = 0.19

or

x = (-4-√44)/14

x = (-4-6.63)/14

x = -10.63/14

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3 0
3 years ago
A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of
jenyasd209 [6]

Answer:

Ix = Iy = \frac{ρπR^{4} }{16}

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Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is \frac{MR^{2} }{2}. Moment of inertia of quarter disk about its perpendicular is \frac{MR^{2} }{8}.

Now using perpendicular axis theorem, Ix = Iy = \frac{MR^{2} }{16} = \frac{ρπR^{4} }{16}.

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

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3 years ago
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Answer:

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Step-by-step explanation:

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