$6x^2-x=2\implies 6x^2-1x-2=0 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{6}x^2\stackrel{\stackrel{b}{\downarrow }}{-1}x\stackrel{\stackrel{c}{\downarrow }}{-2}=0 \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$x = \cfrac{ -(-1) \pm \sqrt { (-1)^2 -4(6)(-2)}}{2(6)}\implies x = \cfrac{1\pm\sqrt{1+48}}{12} \\\\\\ x = \cfrac{1\pm\sqrt{49}}{12}\implies x = \cfrac{1\pm 7}{12}\implies x = \begin{cases} \frac{8}{12}\to &\frac{2}{3}\\[1em] -\frac{6}{12}\to &-\frac{1}{2} \end{cases}$

7 0

2 years ago

Does anybody know this? Find the slope of the line shown

alukav5142 [94]

The slope of the linear function shown is of -1/3.

<h3>What is a linear function?</h3>

A linear function, in slope-intercept formula, is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

Given two points of a line, the slope is given by <u>change in y divided by change in x</u>.

In this problem, the line goes through points (-3,0) and (0,-1), hence the slope is given by:

m = (0 - (-1))/(-3 - 0) = 1/-3 = -1/3.

More can be learned about linear functions at

brainly.com/question/24808124

#SPJ1

8 0

1 year ago