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olya-2409 [2.1K]
4 years ago
10

A 10-ounce box of cereal costs $3. A 20-ounce box of the same cereal costs $5. A third box of the same cereal costs $8. Calculat

e the number of ounces in the third box of cereal.
Mathematics
1 answer:
kogti [31]4 years ago
7 0

Answer:

number of ounces in the third box = 32 ounces

Step-by-step explanation:

The number of ounces is directly proportional to the cost

Let O represent the number of ounces, C represent the cost

O∝C----------------Eqn 1

O = KC

K = O÷C = 20/5 = 4

Hence number of ounces in the third box = 4 × 8 = 32 ounces

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3 years ago
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Ivahew [28]

Answer:

2.3554335e+42

Step-by-step explanation:

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4 years ago
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Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t
Neporo4naja [7]

Answer:

V=61.66

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

f(x)=g(x)\\ln(x)=\frac{1}{2}x-2

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\

and by replacing in the integral we have

V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\

V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]  

and by evaluating in the limits we have

V=61.66

Hope this helps

regards

3 0
3 years ago
Does 4/8 +7/8=11/16 or 11/8
ss7ja [257]
That's easy it is 11/8 because 4+7=11 8 will be the same
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3 years ago
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At top speed jaguar can run 2.5 miles in 3 mins what is it’s speed in mph
Alekssandra [29.7K]

Answer:

50 mph

Step-by-step explanation:

<u>Speed of Jaguar given:</u>

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  • Speed in mph = ?

<u>Solution:</u>

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4 years ago
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