Here is the solution of the given problem above.
Given: Weight of single calf = weight of mother + 3.8%
Weight of mother = 3.75 tons or 7,500 pounds
? = weight of the calf
First, we need to find the 3.8% of 7,500 pounds. The result is 285 pounds.
So to get the weight of the calf, let's add 7,500 pounds to 285 pounds and the result is 7,785 pounds. So the weight of the calf is 7,785 pounds. Hope this helps.
I hope you can understand my messy handwriting
X^2-6x=13
(x-3)^2-9=13
(x-3)^2=22
(x-3)= +-sqrt22
x = sqrt22+3 or x = -sqrt22+3
Answer:
9.5
Step-by-step explanation:
If c to a is 19 then you divide the distance by 2 and you get 9.5 for the two distances.
The temperature was in the range of 10-13 on 7 of the days.
Give it the weight of the middle of the range = 11.5 for 7 times = 80.5
The temperature was in the range of 14-17 on 9 of the days.
Give it the weight of the middle of the range = 15.5 for 9 times = 139.5
The temperature was in the range of 18-21 on 16 of the days.
Give it the weight of the middle of the range = 19.5 for 16 times = 312
The temperature was in the range of 22-25 on 22 of the days.
Give it the weight of the middle of the range = 23.5 for 22 times = 517
The temperature was in the range of 26-29 on 6 of the days.
Give it the weight of the middle of the range = 27.5 for 6 times = 165
Total weight for all ranges = (80.5 + 139.5 + 312 + 517 + 165) = 1,214
Total number of days = 60
Estimated mean temperature = (1,214) / (60) = <u>20.23°C </u>
