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jarptica [38.1K]
3 years ago
8

Rearrange the equation current = voltage/resistance to express resistance in terms of current and voltage. Then solve the follow

ing: A certain device in a 130-V circuit has a current rating of 10 A . What is the resistance of the device (how many ohms)?
Physics
1 answer:
MissTica3 years ago
3 0

Answer:

Resistance, R = 13 ohms

Explanation:

The Ohm's law gives the direct relationship between the voltage, current and the resistance of the device. The relation is as follows :

V=IR

Where

I is the current

r is the resistance

The value of resistance is given by :

R=\dfrac{V}{I}

According to given data,

Voltage of the circuit, V = 130 V

Current rating of the circuit, I = 10 A

Resistance of the device,

R=\dfrac{130\ V}{10\ A}

R = 13 ohms

So, the resistance of the device is 13 ohms. Hence, this is the required solution.

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ale4655 [162]

Answer:

5.0 atm

Explanation:

P₁V₁=P₂V₂

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P₂=5

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3 years ago
An oscillator consists of a block attached to a spring (k = 427 N/m). At some time t, the position (measured from the system's e
White raven [17]

Answer:

a) 4.49Hz

b) 0.536kg

c) 2.57s

Explanation:

This problem can be solved by using the equation for he position and velocity of an object in a mass-string system:

x=Acos(\omega t)\\\\v=-\omega Asin(\omega t)\\\\a=-\omega^2Acos(\omega t)

for some time t you have:

x=0.134m

v=-12.1m/s

a=-107m/s^2

If you divide the first equation and the third equation, you can calculate w:

\frac{x}{a}=\frac{Acos(\omega t)}{-\omega^2 Acos(\omega t)}\\\\\omega=\sqrt{-\frac{a}{x}}=\sqrt{-\frac{-107m/s^2}{0.134m}}=28.25\frac{rad}{s}

with this value you can compute the frequency:

a)

f=\frac{\omega}{2\pi}=\frac{28.25rad/s}{2\pi}=4.49Hz

b)

the mass of the block is given by the formula:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}\\\\m=\frac{k}{4\pi^2f^2}=\frac{427N/m}{(4\pi^2)(4.49Hz)^2}=0.536kg

c) to find the amplitude of the motion you need to know the time t. This can computed by dividing the equation for v with the equation for x and taking the arctan:

\frac{v}{x}=-\omega tan(\omega t)\\\\t=\frac{1}{\omega}arctan(-\frac{v}{x\omega })=\frac{1}{28.25rad/s}arctan(-\frac{-12.1m/s}{(0.134m)(28.25rad/s)})=2.57s

Finally, the amplitude is:

x=Acos(\omega t)\\\\A=\frac{0.134m}{cos(28.25rad/s*2.57s )}=0.45m

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How does the function of the parts of the system contribute to its function as a whole
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3 years ago
5. Two charged particles are separated by a distance of 12 meters. The Coulomb force between them is 20 N. What will the Coulomb
Leni [432]

Answer:

A) 80 N

Explanation:

The closer the particles get, the stronger the Coulomb force, which elongates choices C and D. The Coulomb force is inversely proportional to the distance squared. If the distance is cut in half, the force is multiplied by the reciprocal of (1/2)^2, which is 4. Multiplying it out, 20 times 4 is 80 N.

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If the momentum of an object is doubled then kinetic energy is ...?​
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