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Elden [556K]
3 years ago
10

What is the difference between Groups and Periods?

Physics
1 answer:
Furkat [3]3 years ago
7 0

Science. Groups and periods are two ways of categorizing elements on the periodic table. ... Periods are horizontal rows (across) the periodic table, while groups are vertical columns (down) the table. Atomic number increases both as you move down a group or across a period

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3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
Eduardwww [97]

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

x=\frac{v_{i}^{2}sin(2\alpha)}{g} (1)

Donde:

  • v(i) es la velocidad inicial del cañon (82 m/s)
  • α es el ángulo de tiro
  • g es la gravedad (9.81 m/s²)
  • x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

sin(2\alpha)=\frac{xg}{v_{i}^{2}}

sin(2\alpha)=\frac{560*9.81}{82^{2}}

sin(2\alpha)=0.82

\alpha=\frac{sin^{-1}(0.82)}{2}

\alpha=27.39^{\circ}

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

v_{x}=\frac{x}{t}

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

v_{i}cos(\alpha)=\frac{x}{t}

t=\frac{x}{v_{i}cos(\alpha)}

t=\frac{560}{82cos(27.39)}

t=7.69\: s

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

3 0
3 years ago
Three students each hold basketballs with the same masses at varying heights. One basketball is held 2 feet above the ground. An
Advocard [28]

The Basketball with the greatest gravitational potential energy is : Basketball 4 feet above the ground ( c )

<u>Given data :</u>

masses = constant

H₁ = 2 ft

H₂ = 3 ft

H₃ = 4 ft

g = 9.81 m/s²

<h3><u>Procedure to determine the basketball with the greatest gravitational P.E </u></h3>

we will apply the equation below

Gravitational potential energy ( U ) = mgh

  • For ball 1

U = 2 * 9.81 = 19.62

  • For ball 2

U = 3 * 9.81 = 29.43

  • For ball 3

U = 4 * 9.81 = 39.24

From the calculations the basketball with the greatest gravitational potential  energy is the basketball at 4ft above the ground

Learn more about gravitational potential energy : brainly.com/question/15896499

4 0
3 years ago
What is the difference between cytology and histology
bulgar [2K]

Explanation:

what is the difference between cytology and histology

Histology involves the study of tissue and Cytology involves the study of cells, both of which are derived from various organs of the human body. The Histology laboratory is responsible for the preparation of tissue for diagnosis by Pathologists.

8 0
3 years ago
Where might someone with a pharmaceutical manufacturing career work?
klemol [59]

Answer:  People with careers in pharmaceutical manufacturing can expect to work in: research laboratories or manufacturing plants, and to maintain work hours during the day.

Explanation:

8 0
3 years ago
Find the kinetic energy of a 0.1-kilogram toy truck moving at the speed of 1.1 meters per second.
Viktor [21]

Answer:

0.061 J

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

For the toy truck in the problem, we have

m = 0.1 kg is its mass

v = 1.1 m/s is its speed

Putting the numbers into the equation, we find

K=\frac{1}{2}(0.1 kg)(1.1 m/s)^2=0.061 J

6 0
4 years ago
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