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Angelina_Jolie [31]
2 years ago
9

Convert the following decimal numbers into their binary equivalent: a. 13

Computers and Technology
1 answer:
o-na [289]2 years ago
5 0

Answer: a. 1101 b. 10000 or 101010 c. 100100100 d. 1100 e. 111101 f. 1111000 g. 11101 h. 101100 1000011 1100010

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garik1379 [7]

Answer:

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Explanation:

Router. A router is a networking device typically used to interconnect LANs to form a wide area network (WAN) and as such is referred to as a WAN device. IP routers use IP addresses to determine where to forward packets. An IP address is a numeric label assigned to each connected network device.

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6 0
2 years ago
Wyjaśnij w jaki sposób wykonuje się nitowanie zakładkowe i nakładkowe, oraz wyjaśnij na czym polega pasowanie mieszane.
Ksenya-84 [330]

Answer:

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Explanation:

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3 years ago
An isp is a group of updates, patches, and fixes that apply to specific oss.
olasank [31]
<span>The statement that an ISP is a group of updates, patches, and fixes that apply to specific OSs is false.
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4 0
3 years ago
1. During the first scene, Taylor's mother says "What you do online isn't exactly private." What do you think she meant by that?
tekilochka [14]

Answer:

The statement is "True".

Explanation:

Explanation of this statement can be given as:

  • Taylor's mother meant that the "universe is open to everything you do online, everyone can see". This statement true, because people will hack your profile unless you label these as personal, even re-post material that you have shared.  
  • In other words, we can say that a profile is placed on private in social media, it's not always free and your friend can use it, and they can share your personal information. It is difficult to uninstall once it is out there.  
5 0
3 years ago
Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs
marishachu [46]

Answer:

  1.    public static String bothStart(String text1, String text2){
  2.        String s = "";
  3.        if(text1.length() > text2.length()) {
  4.            for (int i = 0; i < text2.length(); i++) {
  5.                if (text1.charAt(i) == text2.charAt(i)) {
  6.                    s += text1.charAt(i);
  7.                }else{
  8.                    break;
  9.                }
  10.            }
  11.            return s;
  12.        }else{
  13.            for (int i = 0; i < text1.length(); i++) {
  14.                if (text1.charAt(i) == text2.charAt(i)) {
  15.                    s += text1.charAt(i);
  16.                }else{
  17.                    break;
  18.                }
  19.            }
  20.            return s;
  21.        }
  22.    }

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0
3 years ago
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