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3 years ago

I been working on Thai forever Edna I get help

Mathematics

2 answers:

julia-pushkina [17]3 years ago

4 0

Answer:

what do you mean by working on Thai forever?

Step-by-step explanation:

Helga [31]3 years ago

4 0

Answer:

8x- 160=8x+ 180 answerrrrrrrrrrrrrrrrrr

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it costs $4 to enter the fair. each ride costs $2.50. You have $21.50. how many rides can you ride? write a equation

Shalnov [3]

Answer:

7 rides

Equation 21.50 = 2.50x + 4

Step-by-step explanation:

21.50 - 4 = 17.50

17.50/2.50 = 7

21.50 = 2.50x + 4

x is the amount of rides

If this helps, please consider giving me brainliest

3 0

3 years ago

Read 2 more answers

Please help will give brainlyisttt

IRINA_888 [86]

Answer:

Either a or c

Step-by-step explanation:

Sorry I'm not entirely sure.

5 0

3 years ago

Read 2 more answers

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$

8 0

3 years ago

Help, I don’t know how to solve this

Inessa [10]

Answer:

a=A/8

Step-by-step explanation:

This MIGHT be the answer, I am 99% sure!

7 0

1 year ago

leo knows that each time a digit moves one place to the left in a whole number the value of the digit is 10 times as much. descr

Serga [27]

Answer:

Leo is true for any numbers (including decimal numbers)

Step-by-step explanation:

* Lets explain how to solve the problem

- In number 256

# 6 is the unit digit (one digit)

# 5 is the ten digit (10 digit)

# 2 is the hundred digit (100 digit)

- If we change the number to 2563

# 6 digit is moved 1 place to the left now its place changed from unit

digit to ten digit (from 1 to 10) that means 6 in the second number

is 10 times the 6 in the first number

# 5 digit is moved 1 place to the left now its place changed from ten

digit to hundred digit (from 10 to 100) that means 5 in the second

number is 10 times the 5 in the first number

# 2 digit is moved 1 place to the left now its place changed from

hundred digit to thousand digit (from 100 to 1000) that means 2

in the second number is 10 times the 2 in the first number

- In number 2.345

# 2 is the unit digit (one digit)

# 3 is the tenth digit (1/10 digit)

# 4 is the hundredth digit (1/100 digit)

# 5 is the thousandth digit (1/1000 digit)

- If we change the number to 23.45

# 3 digit is moved 1 place to the left now its place changed from tenth

digit to unit digit (from 1/10 to 1) that means 3 in the second number

is 10 times the 3 in the first number

# 4 digit is moved 1 place to the left now its place changed from

hundredth digit to tenth digit (from 1/100 to 1/10) that means 4 in the

second number is 10 times the 5 in the first number

# 5 digit is moved 1 place to the left now its place changed from

thousandth digit to hundredth digit (from 1/1000 to 1/100) that means

5 in the second number is 10 times the 5 in the first number

∴ Leo is true for any numbers (including decimal numbers)

3 0

3 years ago