A truck weighs 5,400 pounds. An open-wheel race car weighs 1/4 as much. How much does the race car weigh?

2 answers:

6 0

Since 1/4 is equal to 0.25 than you would do 5,400 times 0.25 and get the answer of 13,500.0. So the race car weighs 13,500 pounds.

Softa [21]3 years ago

3 0

5,400 x .25 = 1,350 pounds

I multiplied it with .25 because that's the decimal form of 1/4

You might be interested in

Which type of number is 12

telo118 [61]

Answer:

Composite a aa a a a a a a a a a a a a a a a a a a a a a a aaaaaaaaaaaaaaa

4 0

4 years ago

Read 2 more answers

A figure is broken into a rectangle and a triangle. The triangle has a base of 2 and two-thirds feet and height of 3 feet. The r

ohaa [14]

Answer:

$b=2\frac23\:\sf ft$

Area of triangle = 4 ft²

Area of rectangle = $6\frac23\: \sf ft^2$

Area of irregular figure = $10\frac23\: \sf ft^2$

Step-by-step explanation:

$\begin{aligned}\sf Base\:of\:triangle\:(b) & = 5-2\frac13\\\\& = \dfrac{15}{3}-\dfrac73\\\\ & = \dfrac83\\\\ & = 2\frac23\:\sf ft \end{aligned}$

$\begin{aligned}\sf Area\:of\:a\:triangle & =\dfrac12 \sf \times base \times height\\\\& = \dfrac12 \times b \times 3\\\\ & = \dfrac12 \times \dfrac83 \times \dfrac31\\\\ & = \dfrac{24}{6}\\\\ & = 4\: \sf ft^2\end{aligned}$

$\begin{aligned}\sf Area\:of\:rectangle& =\sf length \times width\\\\& = 5 \times 1\frac13\\\\ & = \dfrac51\times \dfrac43\\\\& = \dfrac{20}{3}\\\\ & = 6\frac23\: \sf ft^2\end{aligned}$

$\begin{aligned} \sf Area\:of\:irregular\:figure & = \sf area\:of\:triangle+area\:of\:rectangle\\\\ & = 4 + 6\frac23\\\\ & = 10\frac23\: \sf ft^2\end{aligned}$