hi!
so the original equation is (x^2 -121) / x+ 11.
Those two equations look similar...
well, we know that the top equation looks like a^2 - b^2, and that equation iis equivalent to this equation: (a+b)(a-b).
So if we factor that out, we get:
( (x + 11) * (x-11) )/ (x + 11)
we can cancel the x+11 on the top and the x+11 on the bottom out.
that leaves us with x-11.
Hope this helped!
Answer:
36 feet.
Step-by-step explanation:
We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is
. We are asked to find the maximum height of the ball.
We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.
To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.
Let us find x-coordinate of parabola using formula
.



So, the x-coordinate of the parabola is
. Now, we will substitute
in our given equation to find y-coordinate of parabola.






Therefore, the maximum height of the ball is 36 feet.
Answer:
y = 8x
Step-by-step explanation:
Given that :
Ornanment are packed in boxes
Number of ornament per box = 8
x = number of boxes packed
y = Number of ornaments
Number of Ornanments packed = (Number ornaments per box * number of boxes packed
y = 8 * x
y = 8x
Answer:
x = 27
Step-by-step explanation:
ΔBRD and ΔQCD are similar, hence the ratios of corresponding sides are equal, that is
= 
note that BD = 26 + 39 = 65
substitute values into the ratio equation
=
( cross- multiply )
65x = 39(x + 18)
65x = 39x + 702 ( subtract 39x from both sides )
26x = 702 ( divide both sides by 26 )
x = 27