For the first line we have a slope of (y2-y1)/(x2-x1)
(2--2)/(1--1)=4/2=2 so we have:
y=2x+b, now solve for b with either of the points, I'll use: (1,2)
2=2(1)+b
b=0 so the first line is:
y=2x
Now the second line:
(1-10)/(4--2)=-9/6=-3/2 so far then we have:
y=-3x/2+b, using point (4,1) we solve for b...
1=-3(4)/2+b
1=-6+b
b=7 so
y=-3x/2+7 or more neatly...
y=(-3x+14)/2
...
The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...
2x=(-3x+14)/2
4x=-3x+14
7x=14
x=2, and using y=2x we see that:
y=2(2)=4, so the solution occurs at the point:
(2,4)
Answer:
san po jan
<h3>step_by istep explanation_</h3>
Answer:
25
Step-by-step explanation:
I don't see a "shown below," so I'm not sure if I could accurately answer your question. However, if your graph point is (x,-3), then it wants you to move your graphed point up two units. I believe that would be y = x -1? I'm not sure
Answee:
We have these two equations:
-2x +4y =-22
2x + 8y -26
We need to try to get the same number multiplying both x or y, I think we can make the 2 of the first equation negative, for that, we multiply all the equation by -1:
2x + 8y =-26 ---- -2x - 8y =26
Now we have this:
-2x +4y = -22
-2x -8y = 26
Now e substract both equations:
-2x - (-2x) +4y -(-8y) = -22-26
12y = -48
Y = -48/12 = -4
And we replace to get x
-2x + 4y = -22
-2x +4*(-4)=-22
-2x - 16 = -22
x= -6/-2 =3
