All categories

2 years ago

What is the perimeter of the triangle expressed as a polynomial? 3x+4, x-10, 5x-2

1 answer:

6 0

Your answer is 9x-8.

3x+4, x-10, 5x-2. If you combine the x's you get 9x. You can combine the numbers however you'd like. I chose to combine +4 and -2. That's 2. 2-10 = -8. Therefore your answer is 9x-8.

You might be interested in

Help, help help. just give answers

Fynjy0 [20]

To solve this problem, there are a couple things we need to do. First of all, we need to figure out how much more she's running every day. On day 1, she ran 3/16 of a mile. On day 2, she ran 3/8 of a mile. On day 3, she ran 9/16 of a mile.

How much are we adding each time? To find that out, we need all of our fractions to have the same denominator so we can compare. Let's give 3/8 a denominator of 16. 8*2=16. What you do on one side of the fraction bar, you MUST do to the other: 3*2=6. So, 3/8 = 6/16.

Day 1: 3/16. Day 2: 6/16. Day 3: 9/16. Now do you see the pattern? Every day, she runs 3/16 of a mile more. That's the answer to part 1: 3/16.

So, how long will it take her to get over 1 mile? Let's continue. Day 3: 9/16. Day 4: 9+3=12, so that's 12/16. Day 5: 15/16. Day 6: 18/16! Since the numerator is bigger than the denominator, guess what? That's more than one mile!! So on the 6th time she runs, she ran 18/16 miles. Keep in mind that 18/16 = 9/8 = 1 1/8 miles.

Answers: 3/16; 6th; 1 1/8 (or 9/8)

5 0

3 years ago

Read 2 more answers

A basketball player makes a free throw 82.6% of the time. The player attempts 5 free throws. Use a histogram of the binomial dis

DiKsa [7]

Answer:

The most likely outcome is exactly 4 free throws

Step-by-step explanation:

Given

$n = 5$ --- attempts

$p = 82.6\%$ ---- probability of a successful free throw

$p = 0.826$

Required

A histogram to show the most likely outcome

From the question, we understand that the distribution is binomial.

This is represented as:

$P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}$

For x = 0 to 5, where x represents the number of free throws; we have:

$P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(X = 0) = ^5C_0 * 0.826^0 * (1 - 0.826)^{5-0}$

$P(X = 0) = ^5C_0 * 0.826^0 * (0.174)^{5}$

$P(X = 0) = 1 * 1 * 0.000159 \approx 0.0002$

$P(X = 1) = ^5C_1 * 0.826^1 * (1 - 0.826)^{5-1}$

$P(X = 1) = ^5C_1 * 0.826^1 * (0.174)^4$

$P(X = 1) = 5 * 0.826 * 0.000917 \approx 0.0038$

$P(X = 2) = ^5C_2 * 0.826^2 * (1 - 0.826)^{5-2}$

$P(X = 2) = ^5C_2 * 0.826^2 * (0.174)^{3}$

$P(X = 2) = 10 * 0.682 * 0.005268 \approx 0.0359$

$P(X = 3) = ^5C_3 * 0.826^3 * (1 - 0.826)^{5-3}$

$P(X = 3) = ^5C_3 * 0.826^3 * (0.174)^2$

$P(X = 3) = 10 * 0.5636 * 0.030276 \approx 0.1706$

$P(X = 4) = ^5C_4 * 0.826^4 * (1 - 0.826)^{5-4}$

$P(X = 4) = 5 * 0.826^4 * (0.174)^1$

$P(X = 4) = 5 * 0.4655 * 0.174 \approx 0.4050$

$P(X = 5) = ^5C_5 * 0.826^5 * (1 - 0.826)^{5-5}\\$

$P(X = 5) = ^5C_5 * 0.826^5 * (0.174)^0$

$P(X = 5) = 1 * 0.3845 * 1 \approx 0.3845$

From the above computations, we have:

$P(X = 0) \approx 0.0002$

$P(X = 1) \approx 0.0038$

$P(X = 2) \approx 0.0359$

$P(X = 3) \approx 0.1706$

$P(X = 4) \approx 0.4050$

$P(X = 5) \approx 0.3845$

See attachment for histogram

<em>From the histogram, we can see that the most likely outcome is at: x = 4</em>

<em>Because it has the longest vertical bar (0.4050 or 40.5%)</em>

3 0

2 years ago

For rectangle PLNE, m

FinnZ [79.3K]

Is that the entire question??

4 0

2 years ago

Is 94.598 greater than 94.643?

Schach [20]

Answer:

Step-by-step explanation:

94.643 is bigger than 94.598

if you have 94.643 and have 94.598

subtract 94.643 and 94.598 witch =00.45 so 94.643 is greater than 94.598

hope this helps

7 0

2 years ago

Leah measured the elementary school and made a scale drawing. She used the scale 1 centimeter : 4 meters. The school yard is 60

spayn [35]

Answer: 15 meters

Step-by-step explanation:

1cm/4m= X cm/ 60 m

Cross multipsy

4x=60

Divide by 4

X=15

6 0

3 years ago