a. What percent of people earn less than $40000?
Solution: Let S be the random variable of a salary of employee (in $), S ~ N(50000,20000). Then the random
variable X =−50000
20000
~N(0,1).
( < 40000) = ( <
40000 − 50000
20000 ) = ( < −0.5) = (−0.5) = 0.3085375.
Here Φ(x) denotes the cumulative distribution function of a standard normal distribution.
Answer: 31%.
b. What percent of people earn between $45000 and $65000?
Solution:
(45000 < < 65000) = (
45000 − 50000
20000 < <
65000 − 50000
20000 ) = (−0.25 < < 0.75)
= (0.75) − (−0.25) = 0.7733726 − 0.4012937 = 0.3720789.
Answer: 37%.
c. What percent of people earn more than $70000?
Solution:
( > 70000) = ( >
70000 − 50000
20000 ) = ( > 1) = 0.8413447.
Answer: 84%.
I hope I helped! :) :) :)
Answer:
(x2-x1)+(y2-y1)
Step-by-step explanation:
X2=0
X1=1
y2=9
y1=6
(0-1)+(9-6)
-1+3
2
Answer:
x-values
independent variable
Step-by-step explanation:
x (the independent variable) is the domain
y (the dependent variable) is the range
Answer:
Very little.
Step-by-step explanation:
If you have 1x1=1, and change a number, there is no way that you will get the answer right to be 1.