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Helen [10]
3 years ago
14

medal How many possibilities are there when you roll a die and draw a card from a standard deck of cards? A. 58 B. 112 C. 312 D.

284
Mathematics
2 answers:
WITCHER [35]3 years ago
4 0

Answer:

The correct option is C.

Step-by-step explanation:

If a die is rolled then the total possible outcomes are 1,2,3,4,5,6. Number of total outcomes is 6.

If a card is drawn from a standard deck of cards, then the total number outcomes is 52.

If we roll a die and draw a card from a standard deck of cards, then the total number of possibilities is

T=6\times 52

T=312

Total possible ways to roll a die and draw a card from a standard deck of cards is 312. Therefore the correct option is C.

juin [17]3 years ago
3 0
It is C.312 because you multiply 6 by 52

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Answer:

we conclude that:

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Step-by-step explanation:

Given the expression

3\sqrt{125}+4\sqrt{20}

Combining the radical expressions

3\sqrt{125}+4\sqrt{20}

let us first solve

3\sqrt{125}

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Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

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Apply radical rule:   \sqrt{a^2}=a,\:\quad \:a\ge 0

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similarly solving

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Apply radical rule:  \sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0

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3\sqrt{125}=15\sqrt{5}

4\sqrt{20}=8\sqrt{5}

so the expression becomes

3\sqrt{125}+4\sqrt{20}=15\sqrt{5}+8\sqrt{5}        ∵ 3\sqrt{125}=15\sqrt{5} , 4\sqrt{20}=8\sqrt{5}

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3\sqrt{125}+4\sqrt{20}=23\sqrt{5}    

Hence, the last option i.e. 23\sqrt{5} is correct.                    

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