The formula for the vertical height, h, attained with a vertical take off speed of u is
u² - 2gh = 0
where
g = 9.8 m/s², acceleration due to gravity.
Because h = 1.29 m, therefore
u² = 2*9.8*1.39 = 27.244
u = 5.2196 m/s
Also, the time of flight, t, required when the vertical take-off speed is u is given by
ut - 0.5gt² = 0.
Therefore
5.2196t - 0.5*9.8*t² = 0
5.2196t - 4.9t² = 0
t(5.2196 - 4.9t) = 0
t = 0, or t = 5.2196/4.9 = 1.0652 s
t = 0 corresponds to take-off.
t = 1.0652 s corresponds to landing.
The hang time is 1.0652 s.
Answer:
Take-off speed = 5.22 m/s (nearest hundredth)
Hang time = 1.065 s (nearest thousandth)
Answer:
d & e
Step-by-step explanation:
“How many groups of 4/5 are in 1?”
In fact, there are actually 1/(4/5) groups of 4/5 in 1 = 1.25
The correct answers are d & e
Answer:
Step-by-step explanation:
Surface area=2*(lb+lh+bh)
=2*( 5*4 + 5*1.5 + 4*1.5)
=2* ( 20 + 7.5 + 6.0)
= 2 * 33.50
= 67.0 = 67 square units
Answer:
Product is 6x³ - 37x² + 53x + 8
Step-by-step explanation: