What is the domain of F(x)

Mathematics

1 answer:

nydimaria [60]3 years ago

4 0

The domain of F(x) is all real numbers.

This is due to the fact that the function has no undefined points or domain constraints.

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Use mathematical induction to prove that if L is a linear transformation from V to W, then L (α1v1 + α2v2 +· · ·+αnvn)= α1L (v1)

e-lub [12.9K]

Answer:

The proof is shown in the explanation below.

Step-by-step explanation:

Analysis:

The proof by induction focuses on n. In this case, let n = 1, and $L^{1}$ will be a linear operator since $L^{1} = L$

The exercise will show that $L^{n}$ is a linear operator on V and that $L^{n+1}$ is also a linear operator on V. This, follows that:

$L^{n+1} (av) = L(L^{m}(v_{1}+v_{2})\\ = L(L^{m} (v_{1} + L^{m}v_{2})\\ = L(L^{m}v_{1} + L(L^{m}v_{2})\\ = L^{m+1}(v_{1}) + L^{m+1}(v_{2})$

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3 years ago

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kifflom [539]

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3 years ago

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Write 5(6x+4)-2(5x-2) in the form a(bx+c) where a,b and c integers and a>1

Pavel [41]

Answer:

4(5x + 6)

Step-by-step explanation:

To start, let's expand things out, as we cannot learn anything from this form. We get 30x + 20 - 10x + 4, or 20x + 24. To find the GCD (Greatest Common Divisor), we take the terms and try to find the number (or term) that divides them. It must be a constant, because of the 24, and 4 goes into 20 and 24. So, our final answer is 4(5x + 6).

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Step2247 [10]

Answer:

Step-by-step explanation:

(3m-1)(6-a)-(m+3)(6-a)

=3m(6-a)-1(6-a)-m(6-a)+3(6-a)

=18m-3ma-6+a-6m+ma+18-3a

=12m-2ma+12-2a

=2(6m-ma+6-a)