Answer:
Step-by-step explanation:
If you are trying to <u>solve the system of equations</u> then its
(x,y)=(-1,2)
If you are trying to <u>rewrite the system of equations</u> then its
x+6y=11
x-2y=-5
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
a(3b+5x)
Step-by-step explanation:
Factor 3ab+5ax
3ab+5ax
=a(3b+5x)
MARK ME THE BRAINIEST PLEASE!!
Step-by-step explanation:
8x-5= 6x + 1
8x - 6x = 1+5
2x = 6
x= 2/6 = 1/3
x= 0.333
Answer:
9.64ft
Step-by-step explanation:
Since the diagram tends to form...a right angled triangle....;
with PR = 17ft...,PQ = 14ft
then to calculate the length of QR
we use the pythagoras theorem...which is only applicable to right angled triangles
PR^2 = PQ^2 + QR^2
(17)^2 = (14)^2 + QR^2
where we make QR the subject of formula;
QR^2 = (17)^2 - (14)^2
QR = square root of( 289 - 196)
QR = square root of( 93)
;Therefore the length of QR = 9.64ft
