All categories

3 years ago

Plzzzzzzzzz helpppppppp meeeeeeeeee

Mathematics

1 answer:

dalvyx [7]3 years ago

5 0

Answer:

spenca idk the answer g

You might be interested in

Which sequence follows the rule 2n + 6, where n represents the position of a term in a sequence? 6, 8, 12, 18, . . . 6, 12, 18,

melamori03 [73]

ANSWER

8, 10, 12, 14, . . .

EXPLANATION

The given rule for the sequence is :

f(n)=2n+6

The domain for a sequence is the set of natural numbers.

When n=1,

f(1)=2(1)+6=8

When n=2,

f(2)=2(2)+6=10

When n=3,

f(3)=2(3)+6=12

When n=4,

f(4)=2(4)+6=14

Therefore the sequence that follows the given rule is

8, 10, 12, 14, . . .

8 0

3 years ago

Point H is the incenter of triangle ABC. Find BD. a. 7.5<br> b. 8.5<br> c. 9.2<br> d. 9.7

Mademuasel [1]

Check the picture below

notice, using the 30-60-90 rule, since that triangle is a 30-60-90 triangle, we get 11 = 2x

6 0

3 years ago

Read 2 more answers

D₁ vide using x² - 2x² 2× +3× -5 by ×-3 using synthetic division. <br>

Vaselesa [24]

Answer:

Step-by-step explanation:

I think you are trying to use synthetic division for

$x^{4} -2x^{3} -2x^{2} +3x-5$ divided by x-3

First

x -3 = 0 , make it equal to 0 and add 3 to both sides

x = 3

Then we write all the coefficients and continue with

a pattern of multiply by 3 and add to the next coefficient.

See attachment.

5 0

1 year ago

PLZ help me fast 2 mins left

jek_recluse [69]

Answer:

$\sqrt{-5}=i\sqrt{5}$

$\sqrt{-25}=5i$

Step-by-step explanation:

i is an imaginary unit, this means

$i^2=-1$

Rewrite -5 as $5\cdot (-1)=5\cdot i^2,$

then

$\sqrt{-5}=\sqrt{5i^2}=\sqrt{5}\cdot \sqrt{i^2}=\sqrt{5}\cdot i=i\sqrt{5}$

Rewrite -25 as $-25=25\cdot (-1)=25\cdot i^2,$

then

$\sqrt{-25}=\sqrt{25\cdot i^2}=\sqrt{25}\cdot \sqrt{i^2}=5\cdot i=5i$

6 0

3 years ago

2x squared + 9x=-5 i need to solve for x

In-s [12.5K]

$2x^2+ 9x=-5 \\ \\2x^2 + 9x+5 =0 \\\\a=2, \ \ b=9 , \ \ c=5 \\\\\Delta =b^2-4ac = 9^2 -4\cdot 2\cdot 5 = 81-40=41 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-9-\sqrt{41}}{2\cdot 2 }=\frac{-9-\sqrt{41}}{ 4 }\\\\ x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{-9+\sqrt{41}}{2\cdot 2 }=\frac{-9+\sqrt{41}}{4 }$

3 0

3 years ago