OK the problem is focusing on VOLUME and TIME.. you can set up this problem like this... (v1/t1) x (v2/t2). first we plug in what we know. the first container was filled in 4 minutes so this is our "T1". However we weren't giving the volume of the first container but we were given its dimensions. the volume formula is LxWxH. so we plug in 9x11x12 to get 1188. this is our "V1". the same concept applies for the volume of the aquarium. we have its dimensions so just plug in. 24x25x33 = 19800 this is our "V2". the thing we are left trying to find is T2. so now you can do some cross multiplying and division. (T1xV2)/V1 or (4x19800)/1188 and you get 66.67min or 1h and 6.67mins. and thats how long it took to fill the aquarium.
Answer:
y = 
x + 
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
here m = , hence
y = x + c ← is the partial equation
to find c substitute (- 2, 11) into the partial equation
11 = - 
+ c ⇒ c =
y = x + ← equation of line
Answer:
d = 22 - x / 25
Step-by-step explanation:
The first thing is to calculate the tank capacity, we know that per gallon 25 miles are traveled and at 500 miles there were still two gallons, therefore:
500 miles / 25 miles / gallon = 20
and how there were still 2
20 + 2 = 22
the tank has a 22 gallon capacity
Therefore the equation would be:
d = 22 - x / 25
where x is the number of miles traveled.
for example, if they have traveled 500 miles it would be:
d = 22 - 500/25 = 22 - 20
d = 2 gallons
we can verify that it is correct because it is what the statement says
