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3 years ago

14

Match each expression with its greatest common factor. 4a + 8 2a2 + 8a 12a2 − 8a 4 − 6a Greatest Common Factor Expression 4 : 2

: 2a : 4a :

1 answer:

zlopas [31]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

4a + 8 4

2a² + 8a 2a

12a² - 8a 4a

4 - 6a 2

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. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}$

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}$

$\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5$

So B has two solutions of 5 and -1.5.

Now to C!

$\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}$

$\frac{44}{8} = 5.5$

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0

3 years ago

a secant and tangent are drawn to a circle from a common exterior point. If the length is 14 inches and the length of the extern

hoa [83]

Answer:

Correct option: (3) 45

Step-by-step explanation:

Let's call the length of the tangent 'T', the length of the external segment 'E' and the length of the internal segment 'A'.

If we have a secant and a tangent to a circle, we can use the following property:

T^2 = E * (A + E)

If the tangent is 14 inches and the external segment is 4 inches, we have that:

14^2 = 4 * (A + 4)

196 = 4A + 16

4A = 180

A = 45

Correct option: (3)

5 0

3 years ago

Scores on an exam follow an approximately bell shaped distribution with a mean of 76.4 and a standard deviation of 6.1 points. A

Crazy boy [7]

Answer:

b) 95%

Step-by-step explanation:

We have been given that scores on an approximately bell shaped distribution with a mean of 76.4 and a standard deviation of 6.1 points. We are asked to find the percentage of the data that is between 64.2 points and 88.6 points.

First of all, we will find z-scores of each data point as:

$z=\frac{x-\mu}{\sigma}$

$z=\frac{64.2-76.4}{6.1}$

$z=\frac{-12.2}{6.1}$

$z=-2$

Let us find z-score corresponding to normal score 88.6.

$z=\frac{88.6-76.4}{6.1}$

$z=\frac{12.2}{6.1}$

$z=2$

To find the percentage of the data is between 64.2 points and 88.6 points, we need to find area under a normal distribution curve that lie within two standard deviation of mean.

The empirical rule of normal distribution states that approximately 95% of data points fall within two standard deviation of mean, therefore, option 'b' is the correct choice.

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3 years ago

The graph of y = ax 2 + bx + c is shown below. Determine the solution set of 0 = ax 2 + bx + c.

Pavlova-9 [17]

On the graph, it's shown that the function has two real roots. This means that there will be two solutions. So the answer is 1. {0,4}

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3 years ago

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2013 honda gas tank holds 17.2 gallons. how many pounds of carbon dioxide are produced by burning an entire tank of gas

Monica [59]

19.41 because when you subtract 2013 - 17.2 you get 19.41

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4 years ago