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3 years ago

Simplify 7x + 2y - 3x + 4y Factorise 10x - 15 Solve 5p = 3p + 8

Mathematics

1 answer:

vlada-n [284]3 years ago

7 0

Answer:

1. x = -1.5y

2. 5 (2x-3)

3. p = 4

Step-by-step explanation:

1) Simplifying

7x + 2y + -3x + 4y = 0

Reorder the terms:

7x + -3x + 2y + 4y = 0

Combine like terms: 7x + -3x = 4x

4x + 2y + 4y = 0

Combine like terms: 2y + 4y = 6y

4x + 6y = 0

Solving

4x + 6y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6y' to each side of the equation.

4x + 6y + -6y = 0 + -6y

Combine like terms: 6y + -6y = 0

4x + 0 = 0 + -6y

4x = 0 + -6y

Remove the zero:

4x = -6y

Divide each side by '4'.

x = -1.5y

Simplifying

x = -1.5y

Common factor

10x - 15

5 (2x-3)

3) Simplifying

5p = 3p + 8

Reorder the terms:

5p = 8 + 3p

Solving

5p = 8 + 3p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-3p' to each side of the equation.

5p + -3p = 8 + 3p + -3p

Combine like terms: 5p + -3p = 2p

2p = 8 + 3p + -3p

Combine like terms: 3p + -3p = 0

2p = 8 + 0

2p = 8

Divide each side by '2'.

p = 4

Simplifying

p = 4

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I need help with 11 and 12

Yakvenalex [24]

Answer:

Both are inverse pairs

Step-by-step explanation:

Question 11

$g(x)= 4 + \dfrac{8}{5}x$

(a) Rename g(x) as y

$y = 4 + \dfrac{8}{5}x$

(b) Solve for x :

$\dfrac{8}{5}x = y - 4$

(c) Multiply each side by ⅝

$x = \dfrac{5}{8}(y - 4) = \dfrac{5}{8}y - \dfrac{5}{2}$

(d) Switch x and y

$y = \dfrac{5}{8}x - \dfrac{5}{2}$

(e) Rename y as the inverse function

$g^{-1}(x) = \dfrac{5}{8}x - \dfrac{5}{2}$

(f) Compare with your function

$f(x) = \dfrac{5}{8}x - \dfrac{5}{2}\\\\f(x) = g^{-1}(x)$

f(x) and g(x) are inverse functions.

The graphs of inverse functions are reflections of each other across the line y = x.

In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)

Question 12

h(x)= x - 2

(a) Rename h(x) as y

y = x - 2

(b) Solve for x:

x = y + 2

(c) Switch x and y

y = x + 2

(e) Rename y as the inverse function

h⁻¹(x) = x + 2

(f) Compare with your function

f(x) = x + 2

f(x) = h⁻¹(x)

h(x) and ƒ(x) are inverse functions.

The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).

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3 years ago

The function f(x) = 200 × (1.098)x represents a village's population while it is growing at the rate of 9.8% per year.

AlexFokin [52]

The time for the village to dig the new well is about 7 1/2 years. At this time the population doubles from its current size.

<h3>How to graph a function?</h3>

For a function f(x) = y, the steps to draw a graph for the given function are as follows:

Consider certain values of x
Substitute x values in the given function to obtain y values
Plot the x and y values in the graph
Join the points to know the variation.

<h3>Calculation:</h3>

It is given that,

f(x) = 200 × $(1.098)^x$

Village's population growing rate = 9.8%

Creating a table for x and f(x) values:

x: 0 2 4 6 8 10

f(x = 0) = f(0) = 200 × $(1.098)^0$ = 200

f(x = 2) = f(2) = 200 × $(1.098)^2$ = 241

f(x = 4) = f(4) = 200 × $(1.098)^4$ = 291

f(x = 6) = f(6) = 200 × $(1.098)^6$ = 350

f(x = 8) = f(8) = 200 × $(1.098)^8$ = 423

f(x = 10) = f(10) = 200 × $(1.098)^1^0$ = 509

So,

(x, f(x)): (0, 200) (2, 241) (4, 291) (6, 350) (8, 423) (10, 509)

Plotting these points in the graph and joining the points, the graph is shown below.

Finding the time for the village to dig a new well:

It is given that the population doubled from its current size, the village will need to dig new water well.

The current size of the village = 200

If it doubles for a certain time 't' = 400

So,

400 = 200 × $(1.098)^t$

⇒ $(1.098)^t$ = 2

⇒ log $(1.098)^t$ = log 2

⇒ t log(1.098) = 0.301

⇒ t × 0.04 = 0.301

∴ t = 7.525 years

Therefore, the village's population becomes double at the time 7 and half years from now. So, after 7 1/2 years, the village needs to dig a new well.

Learn more about the function and its graph here:

brainly.com/question/4025726

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