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kow [346]
4 years ago
8

What is the answer to question 12

Mathematics
1 answer:
Ray Of Light [21]4 years ago
7 0
The answer is $70 so D
Because $59.5 is 85% of the original price, use 59.5/0.85 to find the original price
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Jasmine wants to use her savings of $1128 to buy video games and music CDs. The total price of the music CDs she bought was $72.
schepotkina [342]

Answer

Find out the number of video games that Jasmine can buy with her savings .

To proof

Let us assume that the number of video games Jasmine can buy  be x .

As given

Jasmine wants to use her savings of $1128 to buy video games and music CDs.

The total price of the music CDs she bought was $72. The video games cost $43 each.

Than the equation becomes

72 + 43× x = 1128

simplify

72 + 43x = 1128

43x = 1128 - 72

43x = 1056

x = \frac{1056}{43}

x = 24.6 (approx)

Take

x = 24

Therefore the maximum number of video games that Jasmine can buy with her savings be 24 .

Hence proved

5 0
4 years ago
Read 2 more answers
Plz answer ...Find f(-3).
Cloud [144]
A, -5 because you can use synthetic division
6 0
3 years ago
Read 2 more answers
Consider a point on the trans-australian highway, where two old wombats live. arrivals of cars at this point follow a poisson di
mafiozo [28]
Given that the arrivals of cars at the trans-australian highway follow a poisson distribution with the average rate of arrivals as 1 car per 12 seconds.

This is a Poisson distribution with a mean of 1 car every 12 seconds.

Part A:

The probability of a Poisson distribution is given by:

P(X=x)= \frac{e^{-\lambda}\lambda^x}{x!}

Given tha one of the old wombats requires 12 seconds to cross the highway, and he starts out immediately after a car goes by. <span>

The probability he will survive is the probability that no car passes through the point in the next 12 seconds.

P(x=0)= \frac{e^{-1}(1)^0}{0!} =e^{-1}=0.368

Therefore, the probability that he will survive is 0.368



Part B:

Given that </span>at the same point of the highway there is another old wombat, slower but tougher than in the previous exercise. He requires 24 seconds to cross the road, but it takes two cars to kill him. (A single car won’t even slow him down. The arrival rate of cars is still one car per 12 seconds.)

Since the arrival rate of cars is one car per 12 seconds, then, in 24 seconds the arrival rate is 2 cars. (i.e. λ = 2)

T<span>he probability that he survives is the probability that 2 cars did not pass through the point.

P(X\neq2)=1-P(X=2)=1- \frac{e^{-2}(2)^2}{2!} =1-0.135=0.865</span>
6 0
3 years ago
A little help would be nice here pls
MArishka [77]

Answer:

11). 3x² -x    12). -5x + 5

Step-by-step explanation:

11). (4x² + x) - (x² + 2x)

4x² + x - x² - 2x

4x² - x² + x - 2x

3x² -x

12). (6x - 3) - (11x -8)

= 6x - 3 - 11x + 8

= 6x - 11x - 3 + 8

= -5x + 5  

6 0
3 years ago
What is this problem
sergeinik [125]

Answer:

m=A-\frac{2n}{Z}

Step-by-step explanation:

Multiply by 2:

2n = Z(A - m)

Divide by Z:

\frac{2n}{Z} =A-m

Subtract A:

-m=\frac{2n}{Z}-A

Multiply by -1:

m=A-\frac{2n}{Z}

3 0
3 years ago
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