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Klio2033 [76]
3 years ago
5

Kim purchased 6 small containers of potato salad and Seth purchased 2 extra large containers of

Mathematics
2 answers:
Archy [21]3 years ago
8 0
2/8 x 6 = 3/2
9/8 x 2 = 9/4
9/4 - 3/2 = 3/4 lbs
eimsori [14]3 years ago
5 0

Kim purchased 6 small containers of potato salad.Small containers weigh \frac{2}{8}.lbs.

Weight of Kim's purchase =6x\frac{2}{8} =\frac{12}{8}.=\frac{3}{2}. lbs

Seth purchased 2 extra large containers of  Potato salad.

Weight of extra large container=\frac{9}{8}.lbs.

Weight of Seth's purchase =2x\frac{9}{8}. =\frac{18}{8}.=\frac{9}{4}.lbs

Difference in weights of Seth and Kim = \frac{9}{4}.-\frac{3}{2}.=\frac{3}{4}.lbs.

Difference in weight = \frac{3}{4}.lbs.

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lys-0071 [83]
Remember, we can do anything to an equation as long as you do it to both sides

and distributive proeprty, reversed
ab+ac=a(b+c)

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minus x from both sides
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divide both sides by (m-1)
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3 0
3 years ago
using two of the number cards from the list, fill in the gaps so that the values are in ascending order
Mademuasel [1]

The two gaps of the series are 236 % and 2.41.

The series is 2(32/100) _, _ , 247/100.

We are given that the series is in ascending order.

Let the missing numbers be x and y respectively.

We know that  2(32/100) = 2.32 in decimal form and 247/100 is 2.47 in decimal form.

Hence, we can write,

2.32 < x < y < 2.47

The given options are:-

231 % = 231/100 = 2.31 < 2.32

Hence, it is not the answer.

0.42 < 2.31

Hence, it is not the answer.

236 % = 236/100 = 2.36 > 2.31

Hence, this is one of the answers.

34 % = 0.34

0.34 < 2.31

Hence, it is not the answer.

0.237 < 2.31

Hence, it is not the answer.

2.41 > 2.32

Hence, this is one of the answers.

24.2 % = 24.2/100 = 0.242 < 2.31

Hence, it is not the answer.

0.36 < 2.31

Hence, it is not the answer.

As, 2.36 < 2.41, hence,

x = 2.36 or 236 % and,

y = 2.41

To learn more about  series, here:-

brainly.com/question/15415793

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6 0
1 year ago
Three more than twice a number r
sukhopar [10]

Answer:

2r + 3

Step-by-step explanation:

probably

8 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
If the area of the rectangle is 90 km?, then what is the value of the missing side?
r-ruslan [8.4K]
I believe it would be B.
Logically, it’s the only one that makes sense,
As 9x10= 90
None of the others have any way to divide or multiply up to the area,
So yes, B.
5 0
3 years ago
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