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balandron [24]
3 years ago
13

Clara needs to purchase a new dress for a dance. There are several malls near her location. She decides to shop for the dress at

Northfield Mall and purchase the dress from one of the stores at that mall.
Which answer best describes the sample and population?




Sample: all available dresses at stores in Northfield Mall
Population: all available dresses at any location in Clara's state

Sample: all available dresses at stores in Northfield Mall
Population: all available dresses near Clara's location

Sample: all available dresses near Clara's location
Population: all available dresses at stores in Northfield Mall

Sample: all available dresses near Clara's location
Population: all available dresses at any location in Clara's state
Mathematics
2 answers:
Darina [25.2K]3 years ago
7 0

Answer:

Population:stores to purchase a new dress for a dance.

sample: malls near her location.

Step-by-step explanation:

Wewaii [24]3 years ago
3 0

Answer:

Sample: all dresses at stores in Northfield Mall

Population: all dresses at any nearby location.

Step-by-step explanation:

We know that the size of the sample is always smaller than the size of the population.

Here Clara needs to purchase a new dress for a dance, so the population will be all the dresses within her location.

She decides to shop for the dress at Northfield Mall and purchase the dress from one of the stores at that mall. This indicates the small sample, that is ideally representative of the population.

So, the best answer would be :

Sample: all dresses at stores in Northfield Mall

Population: all dresses at any nearby location.

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Answer:

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z= \frac{39-34}{2.5}= 2

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) P(X

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So one deviation below the mean we have: (100-68)/2 = 16%

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Step-by-step explanation:

For this case we have a random variable with the following parameters:

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From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

P(34 < X

We can find the number of deviation from the mean with the z score formula:

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And replacing we got

z= \frac{34-34}{2.5}= 0

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And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

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P(X

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So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

P(29 < X

And replacing we got:

z= \frac{29-34}{2.5}= -2

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