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3 years ago

Nine times the sum of 8 and the some number of 117

Mathematics

2 answers:

pshichka [43]3 years ago

6 0

That can be represented as 9(8+117)
117+ 8 is 125
So that means 9 x 125 which is 1125
Hope I helped. Goodluck

Delicious77 [7]3 years ago

3 0

Is it 8+117=125x9=1125

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a sign says that the price marked on all music equipment is 30% off the original price you buy an electric guitar for sale price

prohojiy [21]

The original price is $450.

Step-by-step explanation:

Step 1:

Given details, Discount%, D% = 30 and Selling Price, SP = $315

Step 2:

Write down formula for calculating the Original Price

Selling Price (SP) = Original Price (OP) - Discount (D)

Discount (D) = Original Price (OP) * (D%/100)

Step 3:

Substitute given values in the formula

315 = OP - D

D = $OP \times30/100$

D = 0.3 OP

Step 4:

Substitute value of D in the first formula

315 = OP - 0.3 OP

315 = OP (1 - 0.3) = 0.7 OP

Original Price, OP = 315/0.7 = $450

5 0

3 years ago

Find the equation of a line that is parallel to line g that contains (P, Q).

Fofino [41]

Correct option:

$\boxed{x-y=P-Q}$

<h2>Explanation:</h2>

Given that the line we are looking for is parallel to g, then the slope of that line and g is the same, therefore:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ (x_{1},y_{1})=(-3,2) \\ \\ (x_{2},y_{2})=(0,5) \\ \\ \\ m=\frac{5-2}{0-(-3)}=1$

So we can write the point-slope form of the equation of the line as follows:

$y-y_{0}=m(x-x_{0}) \\ \\ (x_{0},y_{0})=(P,Q) \\ \\ \\ y-Q=1(x-P) \\ \\ y-Q=x-P \\ \\ \\ Arranging: \\ \\ P-Q=x-y \\ \\ \boxed{x-y=P-Q}$

<h2>Learn more:</h2>

Graphying systems of linear equations: brainly.com/question/13799715

#LearnWithBrainly

8 0

2 years ago

Read 2 more answers

6(2x-1) over 5. I need help so help me pleeease

pav-90 [236]

Answer:

(12x - 6)/5

Step-by-step explanation:

6(2x-1)/5 => (12x - 6)/5 because of the distributive property.

You cannot simplify farther after you reach (12x - 6)/5.

3 0

3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

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2 years ago

HELP PLS

masha68 [24]

I think it would be 0°

7 0

2 years ago