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snow_lady [41]
3 years ago
14

Supposed eight out of every 20 students are absent from school lesson five days a year predict how many students would be absent

from school lesson five days a year out of 40,000 students
Mathematics
1 answer:
choli [55]3 years ago
6 0
8 X
----- = ------
20 40000

40000/20=2000
2000*8=16000

X=16000
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Simplify 3×+1(2×-1)2-1(6×)​
trasher [3.6K]

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Hi my lil bunny!

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

Answer =   \boxed {x - 2}

3x +1(2x-1)2-1(6x)

= \boxed {3x + 1 . ( 2x - 1 ) . 2 - 1 (6x) = x - 2}

Steps :

3x + 1 . (2x - 1) . 2 - 1 . (6x)

Remove the parentheses : (a) = a

= 3x + 1 * (2x- 1) * 2 - 1 * 6x

Multiply the numbers : 1 * 2 = 2

= 3x + 2 ( 2x - 1 ) * 6x

Multiply the numbers : 1 * 6 = 6

= 3x + 2 ( 2x - 1 ) -6x

Expand: 2 (2x - 1) :   4x - 2

2 ( 2x - 1 )

Apply the distributive law : a (b - c) = ab - ac

a = 2, b = 2x, c = 1 \\= 2 * 2x - 2 * 1

Simplify 2 * 2x - 2 * 1 : 4x - 2

= = 4x - 2

= 3x + 4x - 2 - 6x

Simplify 3x + 4x - 2 - 6x : x - 2

= x - 2

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●

Have a great day/night!

❀*May*❀

7 0
3 years ago
What is the measure in radians for the central angle of a circle whose radius is 9 cm and intercepted arc length is 7.2 cm
Oksana_A [137]

Answer: 0.8 radians

Step-by-step explanation:

To solve this exercise you must apply the formula shown below:

S=r\theta

Where S is the arc lenght, r is the radius of the circle and \theta is the central angle in radians.

Solve for the central angle:

\theta=\frac{S}{r}

Now, when you susbtitute the value of the arc length and the radius, you obtain that the central angle is:

\theta=\frac{7.2cm}{9cm}=0.8radians

4 0
4 years ago
Read 2 more answers
How do I find the final price
Tema [17]
Add the sales tax from the discounted price
7 0
3 years ago
Read 2 more answers
4/3y = 16 solve the equation​
Lelu [443]

Answer:

cross and multiply

48y=4

divide both sides by48

y=1/12

3 0
3 years ago
(2m+4n)sq - (2m-4n)sq solve using suitable identities.
Annette [7]
I hope it will be a helpful answer

7 0
4 years ago
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