Answer:
B. $2862
Step-by-step explanation:
Using n=5 in the given equation, we get ...
A(5) = 2700 + (5-1)(.015·2700) = 2700 +4(40.50)
A(5) = 2862.00
In year 5, you will have $2862 in the account.
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<em>Comment on the given equation</em>
The given equation tells you the amount in the account at the <em>beginning</em> of the year, before it earns any interest. Since that is the equation given, we presume that is the answer desired. In most "account balance" problems, you are interested in the amount at the <em>end</em> of the interest-earning period.
Answer:
a^2-12a+36
Step-by-step explanation:
;)
First, make a equation in which r= red and b=blue.
So, since in the first box it has 4 red models and one blue model equaling 12,
the first equation looks like 4r+b=12.
The second equation looks like 2r+b=8.
What you would do is try and first solve for r by getting rid of b.
Since both equation has a positive b, you would make one equation have a negative b by multiplying the whole equation by -1.
-1*(2r+b=8)= -2r-b=-8
Add.
4r+b=12
+(-2r-b=-8)
2r=4
r=2
Then, you plug in 2 for the r for any of the original equations.
4(2)+b=12
8+b=12
b=4
or
2(2)+b=8
4+b=8
b=4
So, the red models weigh 2 pounds while the blue models weigh 4.
Answer:
Company one charges $11 + $0.16 per min.
Then if you talk for x minutes, the cost will be:
C₁(x) = $11 + ($0.16 per min)*x
For company two, the prize is $20 + $0.11 per min, and if yo talk for x minutes, the cost will be:
C₂(x) = $20 + ($0.11 per min)*x
Now we want to find the value of x, the number of minutes, such that the cost is the same with both companies.
C₁(x) = C₂(x)
$11 + ($0.16 per min)*x = $20 + ($0.11 per min)*x
($0.16 per min)*x - ($0.11 per min)*x = $20 - $11
($0.05 per min)*x = $9
x = $9/($0.05 per min) = 180 mins
If you speak for 180 minutes, the cost is the same in both companies.