Answer:
no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
Step-by-step explanation:
Let the no of 2kg disks be a.
Let no of 5 kg disks be b.
2a+5b=29
a+b=10
Using substitution, we have
2(10-b) + 5b=29
20-2b+5b=29
20+3b=29
3b=9
b=3
So no of 5 kg disks is 3, and no of 2 kg disks is (10-3) i.e. 7
Imagine a corner of a cube.
It is made of three planes interesting at a single point
The image should help.
In scientific notation, just move the decimal point over however many numbers are in the power.
In 7.003 • 10^4, move the decimal point over 4 places to the right, (or left if it's negative) making it 70,030
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
Answer:
OOF I MEANT A
Step-by-step explanation:
Michelle is in less debt than John
