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3 years ago

M - 2 < -8 or m/8 >1

1 answer:

7 0

So starting with the first inequality, m - 2 < -8, add 2 on both sides of the equation and your first half is m < -6.

Next, with m/8 > 1, multiply both sides by 8 and your second half is m > 8

Putting it together, your answer is m < -6 OR m > 8.

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PLS HELP QUICK!

nikklg [1K]

Answer:

3 x 21

20 x 4 tenths

21 x thirteenth

please mark me as brainlist please

3 0

1 year ago

The distribution of the amount of money spent by students for textbooks in a semester is approximately normal in shape with a me

zimovet [89]

Answer:

Option D) $275

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $235

Standard Deviation, σ = $20

We are given that the distribution of amount of money spent by students is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.975

$P( X < x) = P( z < \displaystyle\frac{x - 235}{20})=0.975$

Calculation the value from standard normal z table, we have,

$P( z < 1.960) = 0.975$

$\displaystyle\frac{x - 235}{20} = 1.960\\x =274.2 \approx 275$

Approximately 97.5% of the students spent below $275 on textbook.

7 0

2 years ago

What are the real zeroes of x3 + 6 x2 – 9x - 54?

o-na [289]

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of $x^3+6x^2-9x-54$

Solving

$x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)$

Taking x^2 common from first 2 terms and -9 from last two terms we get

$=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\$

Taking (x+6) common

$(x+6)(x^2-9)\\$

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

$=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)$

Putting it equal to zero,

$(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\, x=3$

So, Option B 3,-3,-6 is correct.

7 0

2 years ago

The area of a rectangle is 28ft^2, and the length is 5 ft less than three times the width. find the dimensions of the rectangle.

kramer

Answer:

Step-by-step explanation:

The area of a rectangle is

28 ft2

, and the length of the rectangle is

5 ft

less than three times the width. Find the dimensions of the rectangle.

6 0

2 years ago

Round 77.1110969489 to the nearest hundred-thousandth

Nezavi [6.7K]

77.11110 it’s the nearest hundred- thousandth

4 0

1 year ago