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Alexus [3.1K]
3 years ago
12

Sin pi/4 sin pi/6= 1/2(_____ pi/12-cos 5pi/12)

Mathematics
2 answers:
jonny [76]3 years ago
7 0

Answer: sin pi/4 sin pi/6 = 1/2(cos pi/12 - cos 5pi/12)

correct on apex

Vanyuwa [196]3 years ago
3 0

Answer:

sin\frac{\pi}{4}sin\frac{\pi}{6}=\frac{1}{2}(cos\frac{\pi}{12}-cos\frac{5\pi}{12})

Step-by-step explanation:

We are given that

sin\frac{\pi}{4} sin\frac{\pi}{6}

We have to correct value in blank space.

We know that identity

sin xsiny=\frac{cos(x-y)-cos(x+y)}{2}

Using this identity

sin\frac{\pi}{4}sin\frac{\pi}{6}=\frac{cos(\frac{\pi}{4}-\frac{\pi}{6})-cos(\frac{\pi}{4}+\frac{\pi}{6})}{2}

sin\frac{\pi}{4}sin\frac{\pi}{6}=\frac{cos(\frac{3\pi-2\pi}{12}-cos(\frac{3\pi+2\pi}{12})}{2}

sin\frac{\pi}{4}sin\frac{\pi}{6}=\frac{1}{2}(cos\frac{\pi}{12}-cos\frac{5\pi}{12})

Answer:sin\frac{\pi}{4}sin\frac{\pi}{6}=\frac{1}{2}(cos\frac{\pi}{12}-cos\frac{5\pi}{12})

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5. A line crosses through the points (0, 2) and
puteri [66]

Answer:

Option B

Step-by-step explanation:

In order to find the answer you must use the formula for slope, substitute the values, and solve.

P = (0,2) = (x1,y1)

P=(-10,-16)=(x2,y2)

Slope = \frac{y2-y1}{x2-x1}

Substitute:

Slope = \frac{-16-2}{-10-0}

Solve:

-16-2=-16+-2=-18

-10+0=-10

=\frac{-18}{-10}

Reduce:

18\div2=9

10\div2=5

Remember that a negative divided by a positive equals a negative

=-\frac{9}{5}

Hope this helps

3 0
2 years ago
Please help due soon :)
pickupchik [31]
I’m pretty sure the answer is b because the triangles are congruent
3 0
2 years ago
Solve the following using Substitution method<br> 2x – 5y = -13<br><br> 3x + 4y = 15
Digiron [165]

\huge \boxed{\mathfrak{Question} \downarrow}

Solve the following using Substitution method

2x – 5y = -13

3x + 4y = 15

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{array}  { l  }  { 2 x - 5 y = - 13 } \\ { 3 x + 4 y = 15 } \end{array} \right.

  • To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

2x-5y=-13, \: 3x+4y=15

  • Choose one of the equations and solve it for x by isolating x on the left-hand side of the equal sign. I'm choosing the 1st equation for now.

2x-5y=-13

  • Add 5y to both sides of the equation.

2x=5y-13

  • Divide both sides by 2.

x=\frac{1}{2}\left(5y-13\right)  \\

  • Multiply \frac{1}{2}\\ times 5y - 13.

x=\frac{5}{2}y-\frac{13}{2}  \\

  • Substitute \frac{5y-13}{2}\\ for x in the other equation, 3x + 4y = 15.

3\left(\frac{5}{2}y-\frac{13}{2}\right)+4y=15  \\

  • Multiply 3 times \frac{5y-13}{2}\\.

\frac{15}{2}y-\frac{39}{2}+4y=15  \\

  • Add \frac{15y}{2} \\ to 4y.

\frac{23}{2}y-\frac{39}{2}=15  \\

  • Add \frac{39}{2}\\ to both sides of the equation.

\frac{23}{2}y=\frac{69}{2}  \\

  • Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

\large \underline{ \underline{ \sf \: y=3 }}

  • Substitute 3 for y in x=\frac{5}{2}y-\frac{13}{2}\\. Because the resulting equation contains only one variable, you can solve for x directly.

x=\frac{5}{2}\times 3-\frac{13}{2}  \\

  • Multiply 5/2 times 3.

x=\frac{15-13}{2}  \\

  • Add -\frac{13}{2}\\ to \frac{15}{2}\\ by finding a common denominator and adding the numerators. Then reduce the fraction to its lowest terms if possible.

\large\underline{ \underline{ \sf \: x=1 }}

  • The system is now solved. The value of x & y will be 1 & 3 respectively.

\huge\boxed{  \boxed{\bf \: x=1, \: y=3 }}

8 0
2 years ago
Hey !! Can someone please help me with this??
Katyanochek1 [597]

Answer:

8^2 and 4 x 4 x 4

Step-by-step explanation:

4 to the third power, is the same as 4 x 4 x 4.

This is then equal to 64.

8 squared is also equal to 64, making it also an answer.

None of the other ones work.

<em>Hope this helps and have a nice day!! :) :] :D</em>

7 0
3 years ago
4x−1&lt;11 answer my question
Hitman42 [59]

Answer:

Step-by-step explanation:

4 0
2 years ago
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