Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
It will fall betwenn the square root of 169 which is 13 and 196 is 14
Answer:
88ft
Step-by-step explanation:
600 then divid 1,056 and 12 =88ft
+ 456
----------------
1,056
Answer:
106
Explanation:
3a+b2
Substitute the values for the variables:
3(14) + 2(32)
Solve:
3(14) + 2(32)
42 + 64
106