If the following code is executed, what is the output? a = 1 b = 2. c = '3' d = (1, 2., '3') e = [4, 5., '6'] print type(a)
1 answer:
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Answer:
The program to this question can be given as:
Program:
#include <stdio.h> //include header file.
int main() //defining main method
{
char i,j; //defining variable
for (i='a'; i<='e'; i++) //outer loop for column
{
for (j='a'; j<='e'; j++) //inner loop for row
{
printf("%c%c\n",i,j); //print value
}
}
return 0;
}
Output:
image.
Explanation:
- In the above C language program, firstly a header file is included. Then the main method is defined in this, a method contains a char variable that is "i and j". This variable is used in for loop, that is used to print the pattern.
- To print the following patter two for loop is used the outer loop is used for print columns and the inner loop prints row.
- In C language to print character, we use "%c" inside a loop print function is used, that prints characters.
