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Anit [1.1K]
4 years ago
11

How do you solve -5(x+7) is less than -10

Mathematics
1 answer:
Oxana [17]4 years ago
6 0

Answer:

=−5x−45

Step-by-step explanation:

Distribute:

=(−5)(x)+(−5)(7)+−10

=−5x+−35+−10

Combine Like Terms:

=−5x+−35+−10

=(−5x)+(−35+−10)

=−5x+−45

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Answer:

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Step-by-step explanation:

Vertex form of a quadratic is given by:

f(x)=a(x-h)^2+k

Where (h, k) is the vertex and <em>a</em> is the leading coefficient.

We are given that the vertex is (3, 1). Hence, <em>h</em> = 3 and <em>k </em>= 1. By substitution:

f(x)=a(x-3)^2+1

We are also given a point (2, -6). This means that when <em>x </em>= 2, <em>f(x)</em> = -6. Hence:

-6=a((2)-3)^2+1

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Simplify:

-6=a+1

Therefore:

a=-7

Hence, our quadratic is:

f(x) = -7 (x-3)^2 + 1

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