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Arte-miy333 [17]
3 years ago
7

If the mean height of college males was 70" with a standard deviation of 3", approximately what percentage of college males woul

d be between 6'1" and 6'4
Mathematics
1 answer:
ozzi3 years ago
8 0
Multiply 3 & 70 and divide by the answer of 6'1 6'4 you multiply them then your answer
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The Regency Hotel has enough space at its entrance for six taxicabs to line up, wait for guests, and then load passengers. Cabs
maksim [4K]

Answer:

The appropriate solution is:

(1) 22.81 minutes

(2) 0.171

Step-by-step explanation:

According to the question, the values will be:

The service rate of guess will be:

= 5+3.5

= 8.5 \ minutes

The mean arrival rate will be:

\lambda =\frac{60}{5}

  =7.5 \ cabs/hr

The mean service rate will be:

\mu= 7.05 \ cabs/hr

(1)

The average time a cab must wait will be:

⇒ W_q=22.95-\frac{1}{7.05}

⇒       =\frac{161.798-1}{7.05}

⇒       =\frac{160.798}{7.05}

⇒       =22.81 \ minutes

(2)

The required probability will be:

⇒ P(X\geq 6)=\frac{1-2.115}{1-7.5}

⇒                  =\frac{-1.1115}{-6.5}

⇒                  =0.171

6 0
2 years ago
The LCD for the fractions 1/3 , 3/4 ,5/32 , and 8/9 is
TiliK225 [7]
Your LCD is 288.

Thank You,
  Helpingothers
7 0
3 years ago
ANSWER THIS PLEASE I NEED TO GET MY SLEEP I FORGOT ​
alisha [4.7K]

Answer:

x=0.2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write the Quotient for the following 5 1/3 ÷2​
d1i1m1o1n [39]

Answer:

34

Step-by-step explanation:

51/3/2=51x2/3=102/3=34

3 0
2 years ago
Read 2 more answers
Which equation could be used to calculate the sum of the geometric series? One-third + two-ninths + StartFraction 4 Over 27 EndF
kondaur [170]

Answer:

S 5 = StartFraction one-third (1 minus (two-thirds) Superscript 5 Baseline) Over (1 minus two-thirds) EndFraction

Step-by-step explanation:

Given the geometric series:

1/3+2/9+4/27+8/81+16/243

First we must know that the series is a finite series with just 5terms.

Before we can know the formula to calculate sum of the first five terms of the series, we must determine its common ratio (r) first.

r = (2/9)÷1/3 = 4/27÷2/9= 8/81÷4/27

r = 2/9 × 3/1

r = 2/3

Similarly;

r = 4/27×9/2

r = 2/3

Since all values of r is the as them the common ratio is 2/3.

If r< 1 in geometric series, then the formula for finding its sum is applicable

Sn = a(1-rⁿ)/1-r

a is the first term = 1/3

r is the common ratio = 2/3

n is the number of terms = 5

Substituting the values in the formula we have:

S5 = 1/3{1-(2/3)^5}/1-2/3

This gives the requires equation

S 5 = StartFraction one-third (1 minus (two-thirds) Superscript 5 Baseline) Over (1 minus two-thirds) EndFraction

4 0
3 years ago
Read 2 more answers
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